Answer:
sqrt(2)/2
Step-by-step explanation:
Given tan(x)=2-cot(x), find sin(x).
Rewrite in terms of sine and cosine:
sin(x)/cos(x)=2-cos(x)/sin(x)
Multiply both sides by cos(x)sin(x):
sin^2(x)=2sin(x)cos(x)-cos^2(x)
Rewrite cos^2(x) using the identity sin^2(x)+cos^2(x)=1:
sin^2(x)=2sin(x)cos(x)-(1-sin^2(x))
Distribute:
sin^2(x)=2sin(x)cos(x)-1+sin^2(x)
Subtracting sin^2(x) on both sides:
0=2sin(x)cos(x)-1
Add 1 on both sides:
1=2sin(x)cos(x)
Use identity sin(2x)=2sin(x)cos(x) to rewrite right:
1=sin(2x)
Since sin(pi/2)=1, then 2x=pi/2.
Dividing both sides by 2 gives x=pi/4.
So sin(pi/4)=sqrt(2)/2
Since subtracting is the same as adding a negative number, the answer is -12 + (-12). Hope this helps!
Answer:
Minor earthquakes occurred in the country in the last year were<u> 2326</u>.
Step-by-step explanation:
Given:
In the last year, a total of 2727 earthquakes occurred in the country.
Of these, 85.3 % were minor tremors with magnitudes of 3.9 or less on the Richter scale.
Now, to find the minor earthquakes occured in the country last year.
<em>Total earthquakes occurred in the country = 2727.</em>
<em>The percent of minor earthquakes = 85.3%</em>.
Now, to get the number of minor earthquakes:
85.3% of 2727.



<em>The number of minor earthquakes nearest whole number = 2326.</em>
Therefore, minor earthquakes occurred in the country in the last year were 2326.
Answer:
y=20-3x
Step-by-step explanation: