Question

If the length of side of square is 3x-y,what is the area of the square in terms of x.and y?

Answer 1

Answer:

$\large\boxed{A=9x^2-6xy+y^2}$

Step-by-step explanation:

The formula of an area of a square:

$A=s^2$

s - side length

We have s = 3x - y. substitute:

$A=(3x-y)^2$           use (a - b)² = a² - 2ab + b²

$A=(3x)^2-(2)(3x)(y)+y^2=9x^2-6xy+y^2$