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Sliva [168]
3 years ago
5

If the length of side of square is 3x-y,what is the area of the square in terms of x.and y?

Mathematics
1 answer:
shtirl [24]3 years ago
7 0

Answer:

\large\boxed{A=9x^2-6xy+y^2}

Step-by-step explanation:

The formula of an area of a square:

A=s^2

s - side length

We have s = 3x - y. substitute:

A=(3x-y)^2           <em>use </em><em>(a - b)² = a² - 2ab + b²</em>

A=(3x)^2-(2)(3x)(y)+y^2=9x^2-6xy+y^2

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Answer:

Step-by-step explanation:

Domain x^2 - 9 {Solution: - infinity < x < infinity}

Interval notation (- infinity, infinity)

Range of x^2 - 9 (Solution: f(x) is greater than or equal to - 9)

Interval notation (-9, infinity)

Axis interception points of x^2 - 9:

X- intercepts (3, 0) (-3, 0)

Y-intercepts (0, -9)

Vertex of x^2 - 9: Minimum (0, -9)

Solve for f:

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Step 1: Divide both sides by x.

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8 0
1 year ago
Write an equation in point-slope form for each line.<br> (If possible please show work)
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Answer:

so

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Answer:

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Step-by-step explanation:

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Answer:

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