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kiruha [24]
3 years ago
7

Please help me idk this

Mathematics
2 answers:
Oliga [24]3 years ago
8 0

Answer:

0.75

Step-by-step explanation:

vladimir2022 [97]3 years ago
7 0

Answer:

0.75

Step-by-step explanation:

The 4 is the digit representing the hundredths. The digit after that is a 5 which rounds up.

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Gia got some books from Library yesterday she got five books today Gia returned three books Gia has six books how many books did
makvit [3.9K]

Answer: 4


Explanation:


You can write an algebraic expression to represent the sequence with the books in this way:

  • yesterday she got five books: 5
  • today returned three books: - 3
  • how many books did Gia have to begin: n
  • At the end she has six books, which means that you can set an equality:

       n + 5 - 3 = 6

Now you follow these steps to clear the unknown:

  • do the operations in the left side: n + 2 = 6
  • use subtraction property of equality: n = 6 - 2
  • do the operations: n = 4

And that is the number of books whith which Gina started: 4

6 0
3 years ago
I need some help with this.
Alenkasestr [34]

Answer:

b is 16 d is 13

Step-by-step explanation:

ok is a baby girl that can I be happy

7 0
2 years ago
What are the three choices equivalent to 27^4/3
12345 [234]

the answers are B,D and F

8 0
3 years ago
A school debate team has 4 girls and 6 boys. A total of 3 of the team members will be chosen to participate in the district deba
lys-0071 [83]

Answer:

I’m pretty sure the answer is A.

Hope this helps!

7 0
3 years ago
Suppose that you are given a bag containing n unbiased coins. You are told that n-1 of these coins are normal, with heads on one
gladu [14]

Answer:

The (conditional) probability that the coin you chose is the fake coin is 2/(1 + n)

Step-by-step explanation:

Given

Total unbiased coin = n

Normal coins =n - 1

Fake = 1

The (conditional) probability that the coin you chose is the fake coin is represented by

P(Fake | Head)

And it's calculated as follows;

P(Fake | Head) = P(Fake, Head) ÷ P(Head) ----- (1)

Where P(Fake, Head) = P(Fake) * P(Head | Fake)

P(Fake) = 1/n --- because only one is fake

P(Head | Fake) = n/n because all coins (including the fake) have head

So, P(Fake, Head) = P(Fake) * P(Head | Fake) becomes

P(Fake, Head) = 1/n * n/n

P(Fake, Head) = 1/n

P(Head) is calculated by

P(Fake) * P(Head | Fake) + P(Normal) * P(Head | Normal)

P(Fake) * P(Head | Fake) = P(Fake, Head) = 1/n (as calculated above)

P(Normal) * P(Head | Normal) = ½ * (n - 1)/n ----- considering that the coin also has a tail with equal probability as that of the head.

Going back to (1)

P(Fake | Head) = P(Fake, Head) ÷ P(Head) becomes

P(Fake | Head) = (1/n) ÷ ((1/n) + (½(n-1)/n))

= (1/n) ÷ ((1/n) + (½(n-1)/n))

= (1/n) ÷ (1/n + (n - 1)/2n)

= (1/n) ÷ (2 + n - 1)/(2n)

= (1/n) ÷ (1 + n)/(2n)

= (1/n) * (2n)/(1 + n)

= 2/(1 + n)

Hence, the (conditional) probability that the coin you chose is the fake coin is 2/(1 + n)

5 0
3 years ago
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