We have to determine the equivalent factored form for the quadratic polynomial: 2 x² + x - 6 2 x² + x - 6 = 2 x² + 4 x - 3 x - 6 = = 2 x ( x + 2 ) - 3 ( x + 2 ) = = ( x + 2 ) ( 2 x - 3 ). Zero pairs: x + 2 = 0 x = - 2; 2 x - 3 = 0 2 x = 3 x = 3 /2 Answer: The number of zero pairs needed to model this polynomial is : two ( x = - 2 and x = 3/2 ). The equivalent factored form is: ( x + 2 ) ( 2 x - 3 ).
