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Step2247 [10]
3 years ago
14

The candle was 10 inches long when new. Each half hour 3/4 inch of the candle burned away. After 4 hours, how long was the candl

e?
Mathematics
1 answer:
mash [69]3 years ago
3 0
First I would find out how many inches are burned away in 1 hour, 1 1/2 inches. then u multiply 3/4 by 4 to get 3. then u subtract the 3 by 10 to get 7 inches. the answer is 7 inches.
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You place the spring vertically with one end on the floor. You then drop a book of mass 1.50 kg onto it from a height of 0.900 m
Alex777 [14]

Answer:

The value of the maximum distance the spring will be compressed  

x = 0.143 m= 14.3 cm

Step-by-step explanation:

Given data

Mass m = 1.5 kg

h = 0.9 m

k = 1500\frac{N}{m}

Since the book is released from a height h = 0.9 m above the top of the spring. so the total distance

y = h + x

Now in that case for the spring

mg y= \frac{1}{2} k x^{2}

mg(h +x) = \frac{1}{2} k x^{2}

By rearranging the above equation we get

k x^{2}  - 2mgx - 2mg h = 0

Put all the values in above equation we get

1500x^{2}  - 29.43 x - 26.48 = 0

By solving the above equation we get

x = 0.143 m= 14.3 cm

This is the value of the maximum distance the spring will be compressed.

8 0
3 years ago
Which type of business would tend to use bank loans?
trasher [3.6K]
All business due this; probably locally own. 
4 0
3 years ago
Please help me thank you
Hoochie [10]

Answer:

\large\boxed{\sin2\theta=\dfrac{\sqrt3}{2},\ \cos2\theta=\dfrac{1}{2}}

Step-by-step explanation:

We know:

\sin2\theta=2\sin\theta\cos\theta\\\\\cos2\theta=\cos^2\theta-\sin^2\thet

We have

\sin\theta=\dfrac{1}{2}

Use \sin^2\theta+\cos^2\theta=1

\left(\dfrac{1}{2}\right)^2+\cos^2\theta=1\\\\\dfrac{1}{4}+\cos^2\theta=1\qquad\text{subtract}\ \dfrac{1}{4}\ \text{from both sides}\\\\\cos^2\theta=\dfrac{4}{4}-\dfrac{1}{4}\\\\\cos^2\theta=\dfrac{3}{4}\to\cos\theta=\pm\sqrt{\dfrac{3}{4}}\to\cos\theta=\pm\dfrac{\sqrt3}{\sqrt4}\to\cos\theta=\pm\dfrac{\sqrt3}{2}\\\\\theta\in[0^o,\ 90^o],\ \text{therefore all functions have positive values or equal 0.}\\\\\cos\theta=\dfrac{\sqrt3}{2}

\sin2\theta=2\left(\dfrac{1}{2}\right)\left(\dfrac{\sqrt3}{2}\right)=\dfrac{\sqrt3}{2}\\\\\cos2\theta=\left(\dfrac{\sqrt3}{2}\right)^2-\left(\dfrac{1}{2}\right)^2=\dfrac{3}{4}-\dfrac{1}{4}=\dfrac{3-1}{4}=\dfrac{2}{4}=\dfrac{1}{2}

3 0
3 years ago
What is the exact value of the expressions the square root of 180 − the square root of 125 the square root of 5 ? simplify if po
joja [24]
\sqrt{180}-\sqrt{125}+\sqrt5=\sqrt{36\cdot5}-\sqrt{25\cdot5}+\sqrt5\\\\=\sqrt{36}\cdot\sqrt5-\sqrt{25}\cdot\sqrt5+\sqrt5\\\\=6\sqrt5-5\sqrt5+\sqrt5\\\\=\boxed{2\sqrt5}
5 0
3 years ago
Read 2 more answers
Next 3 terms for 192,48,12,3
Ratling [72]

Answer:

The next 3 terms are: \frac{3}{4}, \frac{3}{16}, and \frac{3}{64}

Step-by-step explanation:

6 0
3 years ago
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