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3 years ago

Graph the circle x2 + y2 + 10x + 6y + 18 = 0.

Mathematics

2 answers:

Minchanka [31]3 years ago

7 0

Answer:

see below for a graph

Step-by-step explanation:

Completing the square for x and y terms can help you put this in the standard form.

(x^2 +10x) +(y^2 +6y) = -18

(x^2 +10x +25) +(y^2 +6x +9) = -18 +25 +9 . . . . add square of half linear coefficient

(x +5)^2 +(y +3)^2 = 16 . . . . . . . circle centered at (-5, -3) with radius 4

pashok25 [27]3 years ago

4 0

Answer:

The graph is formed from the equation

(X+5)^2. + (Y+3)^2. = 16

Step-by-step explanation:

Shown by the attachment

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2 years ago

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Answer:

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Step-by-step explanation:

Given equation:

$x^2+(p-3)y^2-4x+6y-16=0$

<u>Standard equation of a circle:</u>

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(where $(a,b)$ is the centre of the circle, and $r$ is the radius)

If you expand this equation, you will see that the coefficient of $y^2$ is always one.

Therefore, $p-3=1$

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<u>Additional information</u>

To rewrite the given equation in the standard form:

$\implies x^2+y^2-4x+6y-16=0$

$\implies x^2-4x+y^2+6y=16$

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