Answer:
Explanation has been given below
Step-by-step explanation:
a) inter arrival times are exponentially distributed with mean 1/n , where n = rate = 1/sec.
probability distribution function is F(t)=n*exp(-n*t).
reference to any kth packet and the (k-1)th packet
the answer is = integration of F(t).dt with limits 0 to 2 = 1 - exp(-2*n) = 1 - exp(-2)
b) t=5 , P(q) = exp(-5)*(5)^q/factorial(q)
probability of fourth call within t=5 seconds is =
that is P(4) P(5) ...... = 1 - ( P(0) P(1) P(2) P(3) ) ; put the values and get the answer.
c) number of calls/rate = 4/n = 4 seconds
Answer:
100 i think
Step-by-step explanation:
Answer:
I would say about 5 or 6 hours.
Step-by-step explanation:
Answer:
Option C) 16(0.5x - 0.75y + 2)
Step-by-step explanation:
16(0.5x - 0.75y + 2) = 16*0.5x - 0.75y*16 + 2 *16
= 8.0x - 12.0y + 32
= 8x - 12y + 32
