We will call an adult ticket <em>a</em>, and a child ticket <em>c</em>.
Since they sold 60 tickets in total, we can form the equation:
a + c = 60
We can also say that the sum of money from the adult tickets and child tickets combined is 460.
Thus we can say
11a + 6c = 460
Now, we must solve our system.
a + c = 60
11a + 6c = 460
6a + 6c = 360
11a + 6c = 460
-5a = -100
a = 20
Thus, (20) + c = 60
c = 40
a = 20 and c = 40
10x^2-170x is the answer I think you're looking for
Not exactly sure which equation you meant:
3(100-b)=6b
300-3b=6b
300=9b
b= about 33
100-3b=6b
100=9b
b=about 11
It's B!------------------------------