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nexus9112 [7]
4 years ago
6

Need help with this. Hope someone can help

Mathematics
1 answer:
ratelena [41]4 years ago
3 0

First, convert all of the cm measurements to m measurements (so they are all the same unit measurement)

2000 cm = 20 m         800 cm = 8m    

<u>Total Perimeter </u>(Note that circumference of a semi-circle is 2 π r/2 = π r)

Add up the lengths of all of the outside edges. I am going to start on the top and move counter-clockwise:

40 + π (10) + 8 + 25 + 8 + (40 - 25 - 10) + 8 + 10 + 8 + π(10)

= 40 + 10π + 41 + (5) + 26 + 10π

= 112 + 20π

= 112 + 62.8

= 174.8

Answer: 174.8 m

<u>Total Area</u>

Split the picture into 5 sections (2 semi-circles, top rectangle, bottom left rectangle, and bottom right rectangle).  Find the area for each of those sections and then add their areas together to find the total area.

2 semi-circles is 1 Circle: A = π · r²  ⇒ A = π(20/2)² =  π(10)²  = 100π  ≈  314

top rectangle: A = L x w  ⇒  A = 40 x 20  = 800

bottom left rectangle: A = L x w  ⇒  A = 25 x 8  = 200

bottom right rectangle: A = L x w  ⇒  A = 10 x 8  = 80

Total = 314 + 800 + 200 + 80  = 1394

Answer: 1394 m²


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Step-by-step explanation:

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What is the value of x in this equation?<br><br> −4x+8=42
Nady [450]

Answer:

x = -8.5

Step-by-step explanation:

-4x+8=42

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4 0
3 years ago
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Prove that for any natural value of n the value of the expression:
Julli [10]

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5 0
3 years ago
A manufacturer of band saws wants to estimate the average repair cost per month for the saws he has sold to certain industries.
vlada-n [284]

Answer:

The average repair cost per saw for the past month is 20.

The bound of error of estimation is ±10.

Step-by-step explanation:

a) Data and Calculations:

Industry        No.of saws   Total repair cost   Average

                                           for past month

1                            3                        50           16.67

2                           7                        110           15.71

3                          11                       230          20.91

4                          9                        140           15.56

5                          2                         60           30

6                         12                       280           23.33

7                         14                       240           17.14

8                          3                         45           15

9                          5                        60           12

10                         9                      230           25.56

11                          8                       140           17.50

12                         6                       130           21.67

13                         3                        70           23.33

14                         2                        50           25

15                         1                          10           10

16                        4                         60           15

17                       12                       280           23.33

18                        6                        150           25

19                        5                         110           22

20                       8                        120           15

Total               130                    2,565           19.73

Average = Sum of the total repair cost for past month divided by the number of saws repaired

= 19.73 (2,565/130)

= 20

The bound on error of estimation = the difference between the upper bound of the interval and the calculated mean

= 30 - 20

= 10

The lower bound = 10

The bound of error is also = (30 -10)/2 = 10

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3 years ago
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sdas [7]

Answer:

£95

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Cost of 11 cushions = £55

Unit cost of 1 cushion = 55/11 = £5 per cushion

Cost of buying 19 cushion = 19 × unit cost

= 19 × £5

= £95

Thus, it would cost £95 to buy 19 cushions

7 0
3 years ago
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