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melisa1 [442]
3 years ago
9

Perpendicular lines must have a negative slope. do perpendicular lines have slopes which have opposite signs.

Mathematics
1 answer:
nordsb [41]3 years ago
6 0
Yes perpendicular lines are negative reciprocals.
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The ratio of the width of the rectangle to the height of the rectangle is ?
Karo-lina-s [1.5K]
The area of a rectangle is 108cm (squared. the ratio of the width to the length is 3:4
4 0
3 years ago
Solve fI the one variable using the distriputive property <br> -6(2+a)=-48
Sloan [31]
Distribute
-12 -6a = -48
Add 12 to isolate -6a
-6a = -36
Divide by -6 on both sides to isolate a
a = 6
6 0
3 years ago
Please help. I’ll mark you as brainliest if correct!
chubhunter [2.5K]

Answer:

\boxed{\sf \ \ \ f^{-1}(x)=1+\sqrt{x} \ \ \ }

Step-by-step explanation:

the minimum of f is for x = 1 and f(1)=0

f is decreasing for x<=1 and increasing for x>=1

so the domain is [1;+\infty[

f^{-1}(f(x))=x =f^{-1}((x-1)^2)\\\\f(f^{-1}(x))=x=(f^{-1}(x)-1)^2

x>=1 so x is positive and we can take the square root

so f^{-1}(x)=1+\sqrt{x}

8 0
3 years ago
Rotation 180 about the origin E(2,-2), J(1,2), R(3,3), S(5,2)​
hammer [34]

E' (-2, 2) , J'(-1, -2) , R'(-3,-3) , S'(-5, -2)

6 0
3 years ago
What is an equation for the linear function whose graph contains the points (−1, −2) and (3, 10)
sladkih [1.3K]
The equation of a line starting from two points is:
y-y_1=\frac{y_2-y_1}{x_2-x_1} \cdot (x-x_1)

From the first point you get: x1 = -1, y1 = -2
From the second point you get: x2 = 3, y2 = 10

Replace x1, y1, x2, y2 in the equation of the line and you get:
y+2=\frac{10+2}{3+1} \cdot (x+1)
y+2=\frac{12}{4} \cdot (x+1)
y+2=3 \cdot (x+1)

From this you get the equation of your line:
y(x)=3x+1




4 0
3 years ago
Read 2 more answers
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