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ch4aika [34]
2 years ago
6

2x^4 + 5x^3 - 8x - 20

Mathematics
1 answer:
Ugo [173]2 years ago
8 0

Answer: factored it is (2x+5)(x^3-4) but the solutions are x=-2.5 and x=1.587

Step-by-step explanation:

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2.75j + 2.25 - 1.5j + 3 simplified
sergiy2304 [10]
You can say 2.75j - 1.5j = 1.25j and 2.25+3 = 5.25 so now you have : 
1.25j + 5.25 and thats simplify :)))
i hope this is helpful 
have a nice day 
4 0
3 years ago
Read 2 more answers
Maymona book club is ordering new novels, She knows that the total cost of 6 books is $90, and 10 books cost $150. Write an equa
aleksandr82 [10.1K]

Answer:

Y=15x

Step-by-step explanation:

<h2>Okay so let's approach this problem!</h2><h2 />

X is books and Y is total cost

Let's find the slope!

Y2-Y1/ X2-X1

Just replace

\frac{150 - 90}{10 - 6}

\frac{60}{4}  = 15

The slope is 15

y = 15x + b

Now replace x and y with coordinates and solve

150 = 15(10) + b \\ 150 = 150 + b \\  - 150 \\ 0 = b

The final equation:

y = 15x

That's it! If you have any questions please ask! Brainliest Appreciated.

6 0
2 years ago
Suppose that from the past experience a professor knows that the test score of a student taking his final examination is a rando
DENIUS [597]

Answer:

n=13.167^2 =173.369 and if we round up to the nearest integer we got n =174

Step-by-step explanation:

Previous concepts

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Let X the random variable who represents the test score of a student taking his final examination. We know from the problem that the distribution for the random variable X is given by:

X\sim N(\mu =73,\sigma =10.5)

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Solution to the problem

We want to find the value of n that satisfy this condition:

P(71.5 < \bar X

And we can use the z score formula given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

And we have this:

P(\frac{71.5-73}{\frac{10.5}{\sqrt{n}}} < Z

And we can express this like this:

P(-0.14286 \sqrt{n} < Z< 0.14286 \sqrt{n} )=0.94

And by properties of the normal distribution we can express this like this:

P(-0.14286 \sqrt{n} < Z< 0.14286 \sqrt{n} )=1-2P(Z

If we solve for P(Z we got:

P(Z

Now we can find a quantile on the normal standard distribution that accumulates 0.03 of the area on the left tail and this value is: z=-1.881

And using this we have this equality:

-1.881 = -0.14286 \sqrt{n}

If we solve for \sqrt{n} we got:

\sqrt{n} = \frac{-1.881}{-0.14286}=13.167

And then n=13.167^2 =173.369 and if we round up to the nearest integer we got n =174

6 0
3 years ago
Find the distance between the points (<br> -<br> 10,12) and (15,12).
Nitella [24]
The distance formula is:

d= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}

We are given two points in the form (x,y), so plug in the values to the distance formula:

d= \sqrt{(-10-15)^2-(12-12)^2}

Next we can simplify. We know that 12-12 is 0, so we can drop it from the equation, as it will not affect our answer. Also, we know that -10-15 is -25:

d= \sqrt{(-25)^2}

The square and square root cancel each other out leaving us with 25.

The answer is 25.


5 0
3 years ago
What is 3 to the powers of 5
My name is Ann [436]

Answer:

3 to the power of 5 = 35 = 243

Step-by-step explanation:

4 0
3 years ago
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