Alright so I'm coming up with this on the fly; you have the first six letters (a,b,c,d,e,f) and 0-9 and your ten numbers. calculate the amount of possible combinations for the letters by simply writing them down.
ab, ac, ad, ae, a f- five
bc, bd , be, bf- four
cd, ce, cf- three
de, df- two
ef,- one.
adding these all together gets a total of 15 for the letters. now the numbers
01, 02, 03, 04, 05, 06, 07, 08, 09- nine
12, 13, 14, 15, 16, 17, 18, 19- eight
23, 24, 25, 26, 27, 28, 29- seven
34, 35, 36, 37, 38, 39- six
45, 46, 47, 48, 49- five
56, 57, 58, 59- four
67, 68, 69- three
78, 79- two
89- one
added together with a total of 45 combinations.
alright so, 45 different number combinations and 15 letter combinations. multiplying 15 by 45 should tell you the total possible combinations for a two letter and two number serial-number
Angle AEB and angle CED are vertical angles, this means they equal each other, therefore we set their values as an equation and solve:
5x-10=3x+40
Subtract 3x to both sides
2x-10=40
Add 10 to both sides
2x=50
Divide both sides by 2
x=25
After we have gotten the value of x we can plug it in into the equation of angle AEB:
5x-10
Substitute x by 25
5(25)-10
Distribute
125-10
Substract
115
The measurement of angle AEB is 115
Hope it helped!, have a great day.
This isn’t a question this is just a statement
2n+2(n-4)=56
2n+2n-8=56
4n-8=56
4n=64
n=16
1st side is 16
2nd side is 12
849-1.5=847.5
6.8-4.8=2
847.5 divided by 2 =423.75
