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ivolga24 [154]
3 years ago
14

The total cost of 8 sharpeners and 3 sketchbooks is $26.05. If the cost of a sharpener is $a, and a sketchbook is $1.90 more exp

ensive,
find A. Give your answer to two decimal places.
Mathematics
2 answers:
koban [17]3 years ago
4 0

Answer:

1.85

Step-by-step explanation:

So, s (sketchbook) is a+1.90.

8a+ 3(a+1.90)=26.05

8a+3a+5.7=26.05

11a=20.35

a=1.85

Check:

8x1.85=14.8

s=11.25

White raven [17]3 years ago
4 0

Answer:

A= 1.85

Step-by-step explanation:

I made an equasion

8(a) + 3(a+1.90) = 26.05

distributed

8a+ 3a + 5.70 = 26.05

Added

11a+ 5.70= 26.05

subtracted

11a= 20.35

divided

a= 1.85

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SAT reading and writing section scores of a random sample of twenty 11th-grade students in a certain high school are given below
kvasek [131]

Answer:

The value of test statistics is 25.

Step-by-step explanation:

We are given below the SAT reading and writing section scores of a random sample of twenty 11th-grade students in a certain high school;

380, 520, 480, 510, 560, 630, 670, 490, 500, 550, 400, 350, 440, 490, 620, 660, 700, 730, 740, 560

<em>Let </em>\sigma<em> = population standard of the reading and writing section SAT score of the students in this school</em>

So, Null Hypothesis, H_0 : \sigma \leq 100     {means that the reading and writing section SAT score of the students in this school is lesser than or equal to 100}

Alternate Hypothesis, H_A : \sigma<em> </em>> 100     {means that the reading and writing section SAT score of the students in this school is higher than 100}

The test statistics that would be used here is <u>One-sample Chi-square</u> test statistics;

                        T.S. =  \frac{(n-1)s^{2} }{\sigma^{2} }  ~ \chi^{2} __n_-_1

where, s^{2} = sample variance =  \frac{\sum (X-\bar X)^{2} }{n-1}  = 13135.8

            n = sample of 11th-grade students = 20

So, <u><em>the test statistics</em></u>  =  \frac{(20-1)\times 13135.8^{2} }{100^{2} }

                                     =  24.96 ≈ 25

Hence, the value of test statistics is 25.

5 0
3 years ago
Parallelogram ABCD has vertices at A(0, 0) , B(4, 5) , C(8, 0) , and D(4,−5) .
Makovka662 [10]

AB = √(5-0)^2 + (4-0)^2 = √25+16 = √41

BC = √(0-5)^2 + (8-4)^2 = √25+16 = √41

CD = √(-5 - 0)^2 + (4-8)^2 = √25+16 = √41

AD = √(-5-0)^2 + (4-0)^2 = √25+16  = √41

All the sides are equal so it is either a square or a rhombus.

The distance from A to C  on the x axis is: 8-0 =  8 units.

The distance from B to D on the Y axis is: 5 - - 5 = 10 units.

Because the two distances are not the same, it is not a square.

The answer is 4. AB=BC ; therefore, ABCD is a rhombus.

3 0
3 years ago
The sum of mike and Jordan’s age is 51. The difference in their ages is 17. If mike is older, what are the two men’s ages?
iogann1982 [59]

Answer:

Step-by-step explanation:

You can make equations.

M+J=51

M-J=17

Subtracting first equation from second equation:

2J=34

J=17 Jordan is 17

Therefore, Mike, is 34.

4 0
3 years ago
6 cousins inherited a total of 58 of their great aunt's assets which they divided evenly what fraction of their great aunt's ass
mina [271]

Answer:

9 1/9 per cousin

Step-by-step explanation:

if the aunt has 58 items to be distributed to 6 cousins, we would set a fraction of 58/6. performing that is 9 with 4/6 left over.

since there is 6 cousins, there will be 2/3 divided by 6 = 2/18, or 1/9

4 0
3 years ago
Anyone wanna help me?
spayn [35]
Similarities: same atomic number
Differences: they have a different number of neutrons
8 0
3 years ago
Read 2 more answers
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