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Temka [501]
3 years ago
15

Which factor affects the heart rate in mammals

Biology
1 answer:
AnnZ [28]3 years ago
7 0


A mammals need for oxygen effects their heart rate because there could be some cases where they're in lack of oxygen causing them to be literally ' out of breath ' . Like climbing a mountain. The higher you go the less oxygen.


Hope I helped !!11!!!!!    :)

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Which of the following is an example of homologous structures?
Mars2501 [29]
The answer would be D. The definition of a homologous structure is an organ or body part that appears in different animals and is similar in structure and location, but doesn't necessarily share the same purpose. The birds and rabbits have similar bones in their forelimbs, but one uses them to run and other uses them to fly.
8 0
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How long does your cerebrum take to fully develop?
crimeas [40]

Answer:

about nine mouths hope this helps

Explanation:

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Why do sex-linked traits follow different patterns of inheritance than other traits?
ANEK [815]

Answer:

I think option (C) is right answer

7 0
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Read 2 more answers
The portion of the brain that is sometimes referred to as the hindbrain is the:
notsponge [240]
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6 0
3 years ago
In a population of rabbits, there are 496 black rabbits and 27 white rabbits. Fur color is determined by a pair of alleles where
Troyanec [42]

Answer:

0.96

Explanation:

It is given that

B is the dominant allele which represents the black color

and b is the recessive allele which represents the white fur.

B being dominant will result into black color fur for genotype "Bb"

Given -

Frequency of black fur allele (p) is 0.8

As per Hardy Weinberg's  first law of equilibrium

p + q = 1\\

Substituting the value of p in above equation, we get -

q = 1-p\\q = 1-0.8\\q= 0.2

q represents the frequency for white fur allele

Frequency of white fur phenotype is

q^2\\= 0.2^2\\= 0.04

Frequency of homozygous black fur phenotype (BB) is

p^2\\= 0.8^2\\= 0.64

As per Hardy Weinberg's second law of equilibrium -

p^2 + q^2 + 2pq = 1\\0.64 + 0.04 + 2pq = 1\\2pq = 1 - 0.68\\2pq = 0.32\\

Combined frequency of homozygous and heterozygous black fur phenotype is

0.64 + 0.32\\= 0.96

5 0
3 years ago
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