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vodka [1.7K]
3 years ago
11

The circumference of the inner circle is 44 ft. The distance between the inner circle and the outer circle is 3 ft. By how many

feet is the circumference of outer circle greater than the circumference of the inner circle? Use 22/7 for pi
Mathematics
1 answer:
Citrus2011 [14]3 years ago
5 0

Answer: 18.86 feet

Step-by-step explanation:

The formula for determining the circumference of a circle is expressed as

Circumference = πD

Where D represents the diameter of the circle.

The circumference of the inner circle is 44 ft. It means that

22/7 × D = 44

22D = 7 × 44 = 308

D = 308/22

D = 14 ft

The distance between the inner circle and the outer circle is 3 ft. This means that the diameter of the outer circle would be

14 + 3 + 3 = 20 ft

Circumference of the outer circle is

22/7 × 20 = 62.86 ft

The number of feet by which the circumference of outer circle is greater than the circumference of the inner circle is

62.86 - 44 = 18.86 feet

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The fill up for the 3rd  step is y - 250 =  340x.

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<h3>What is the simplification  about?</h3>

Note that:

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y = 250 + 340x.

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y - 250 =  340x.

then y-250/340 = x

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The justification for the second step is subtraction property of equality because it undergoes subtraction and the collection of like terms and then subtracting them from one another as shown below:

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Step-by-step explanation:

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The summer monsoon brings 80% of India's rainfall and is essential for the country's agriculture.
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Step 1. Between 688 and 1016mm. Step 2. Less than 688mm.

Step-by-step explanation:

The <em>68-95-99.7 rule </em>roughly states that in a <em>normal distribution</em> 68%, 95% and 99.7% of the values lie within one, two and three standard deviation(s) around the mean. The z-scores <em>represent values from the mean</em> in a <em>standard normal distribution</em>, and they are transformed values from which we can obtain any probability for any normal distribution. This transformation is as follows:

\\ z = \frac{x - \mu}{\sigma} (1)

\\ \mu\;is\;the\;population\;mean

\\ \sigma\;is\;the\;population\;standard\;deviation

And <em>x</em> is any value which can be transformed to a z-value.

Then, z = 1 and z = -1 represent values for <em>one standard deviation</em> above and below the mean, respectively; values of z = 2 and z =-2, represent values for two standard deviations above and below the mean, respectively and so on.

Because of the 68-95-99.7 rule, we know that approximately 95% of the values for a normal distribution lie between z = -2 and z = 2, that is, two standard deviations below and above the mean as remarked before.

<h3>Step 1: Between what values do the monsoon rains fall in 95% of all years?</h3>

Having all this information above and using equation (1):

\\ z = \frac{x - \mu}{\sigma}  

For z = -2:

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For z = 2:

\\ 2 = \frac{x - 852}{82}

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Thus, the values for the monsoon rains fall between 688mm and 1016mm for approximately 95% of all years.

<h3>Step 2: How small are the monsoon rains in the driest 2.5% of all years?</h3>

The <em>driest of all years</em> means those with small monsoon rains compare to those with high values for precipitations. The smallest values are below the mean and at the left part of the normal distribution.

As you can see, in the previous question we found that about 95% of the values are between 688mm and 1016mm. The rest of the values represent 5% of the total area of the normal distribution. But, since the normal distribution is <em>symmetrical</em>, one half of the 5% (2.5%) of the remaining values are below the mean, and the other half of the 5% (2.5%) of the remaining values are above the mean. Those represent the smallest 2.5% and the greatest 2.5% values for the normally distributed data corresponding to the monsoon rains.

As a consequence, the value <em>x </em>for the smallest 2.5% of the data is precisely the same at z = -2 (a distance of two standard deviations from the mean), since the symmetry of the normal distribution permits that from the remaining 5%, half of them lie below the mean and the other half above the mean (as we explained in the previous paragraph). We already know that this value is <em>x</em> = 688mm and the smallest monsoons rains of all year are <em>less than this value of x = </em><em>688mm</em>, representing the smallest 2.5% of values of the normally distributed data.

The graph below shows these values. The shaded area are 95% of the values, and below 688mm lie the 2.5% of the smallest values.

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Answer:The answer below which the image.

Step-by-step explanation:

Hope this helps!!!

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