The circumference of the inner circle is 44 ft. The distance between the inner circle and the outer circle is 3 ft. By how many feet is the circumference of outer circle greater than the circumference of the inner circle? Use 22/7 for pi
1 answer:
Answer: 18.86 feet
Step-by-step explanation:
The formula for determining the circumference of a circle is expressed as
Circumference = πD
Where D represents the diameter of the circle.
The circumference of the inner circle is 44 ft. It means that
22/7 × D = 44
22D = 7 × 44 = 308
D = 308/22
D = 14 ft
The distance between the inner circle and the outer circle is 3 ft. This means that the diameter of the outer circle would be
14 + 3 + 3 = 20 ft
Circumference of the outer circle is
22/7 × 20 = 62.86 ft
The number of feet by which the circumference of outer circle is greater than the circumference of the inner circle is
62.86 - 44 = 18.86 feet
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