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kirill115 [55]
3 years ago
15

What forms of energy are used in making geothermal energy?

Physics
1 answer:
hammer [34]3 years ago
3 0
.....................

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An exoplanet is in an elliptical orbit around a distant star. At its closest approach, the exoplanet is 0.540 AU from the star a
atroni [7]

Answer:

0.71121 km/s

Explanation:

v_1 = Velocity of planet initially = 54 km/s

r_1 = Distance from star = 0.54 AU

v_2 = Final velocity of planet

r_2 = Final distance from star = 41 AU

As the angular momentum of the system is conserved

mv_1r_1=mv_2r_2\\\Rightarrow v_1r_1=v_2r_2\\\Rightarrow v_2=\frac{v_1r_1}{r_2}\\\Rightarrow v_2=\frac{54\times 0.54}{41}\\\Rightarrow v_2=0.71121\ km/s

When the exoplanet is at its farthest distance from the star the speed is 0.71121 km/s.

7 0
3 years ago
If you were asked how to evaluate scientific evidence, what would you would want to include in your answer?
raketka [301]
You would want to include qualitative and quantitative evidence
6 0
4 years ago
What is the work done by a car's braking system when it slows the 1500-kg car from an initial speed of 96 km/h down to 56 km/h i
kondor19780726 [428]

Answer:

-352.275KJ

Explanation:

We are given that

Mass of car=1500kg

Initial speed of car =u=96 km/h=96\times \frac{5}{18}=26.67m/s

1km/h=\frac{5}{18}m/s

Final speed of car=v=56km/h=56\times \frac{5}{18}=15.56m/s

Distance traveled by car=s=55m

We have to find the work done by the car's braking system.

Using third equation of motion

v^2-u^2=2as

(15.56)^2-(26.67)^2=2a(55)

-469.18=110a

a=\frac{-469.18}{110}=-4.27m/s^2

Where negative sign indicates that velocity of car decreases.

Work done by a car's barking system=w=F\times s=ma\times s

Work done by a car's barking system=1500\times -4.27\times 55=352275J

Work done by a car's barking system=-\frac{352275}{1000}=-352.275KJ

1KJ=1000J

Where negative sign indicates that work done in opposite direction of motion.

7 0
4 years ago
Read 2 more answers
How do contact and non-contact forces affect the design of different modes of transportation?
padilas [110]

Contact and non contact forces are big factors to consider in designing of different modes of transportation because this factors are resistances for the mode of transportation. These contact and non- contact forces should be minimized in order for the energy requirement to be also minimum. But not the extent of risking the safety, for example a non contact force is the wieght, the should be optimum, safety of the design should not be compromised just to reduce weight, just like by removing essential parts, support just to remove weight is not good. 

7 0
4 years ago
George Of The Jungle's wife, Mrs. Of The Jungle, has been pestering him to go on a diet. He should have listened. During his com
Elena L [17]

Answer:

112.06 kg - Thats heavy !

Explanation:

Let's do force balance here. Let the object of our interest be George. The forces acting on him are the tension in  the upward direction, his weight in the downward direction and the centrifugal force in the downward direction. Considering the upward and downward directions on the y-axis and f=given the fact that George doesn't move up or down, the forces are balanced along the y-axis. Hence doing force balance:

magnitude of forces upward =magnitude of forces downward

i.e., Tension(T) = Weight(mg) + Centrifugal force (mv²/r)

where: 'm' is the mass of George, g is the acceleration due to gravity (9.8 m/s²). v is the speed with which George moves (14.1 m/s) and r is the radius of the circle in which he's moving at the instant (Here since he's swinging on the rope, he moves in a circle with radius as the length of the rope and hence r=7.3m).

therefore, T = m (9.8 + (14.1)²/7.3) = 4150 N

Therefore, m = 112.06 kg

7 0
3 years ago
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