When a 4.60-kg object is hung vertically on a certain light spring that obeys Hooke's law, the spring stretches 2.30 cm. (a) If
the 4.60-kg object is removed, how far will the spring stretch if a 1.50-kg block is hung on it? cm (b) How much work must an external agent do to stretch the same spring 4.00 cm from its unstretched position?
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The centripetal force experienced by the towel is 55 N.
The given parameters;
- angular speed of the washing machine, ω = 200 rpm
- radius of the machine' drum, r = 0.5 m
- mass of the towel, m = 0.25 kg
The centripetal force experienced by the towel spinning along the walls of the drum is calculated as follows;
Fc = mrω²
where;
<em>Fc is the centripetal force</em>
<em>ω is angular speed in rad/s</em>
The angular speed in rad/s is calculate as;
The centripetal force experienced by the towel is calculated as;
Thus, the centripetal force experienced by the towel is 55 N.
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A car with a velocity of 22 m/s is accelerated at a rate of 1.6 for 6.8s has the final velocity t be 32.88 m/s.
The acceleration means the amount of velocity changing per unit time.
The given data:
initial velocity, u = 22 m/s
time, t = 6.8 s
acceleration, a = 1.6
We will be using the equation of motion:
v = u + at
The final velocity become 32.88 m/s.
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