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4 years ago

15

How do contact and non-contact forces affect the design of different modes of transportation?

1 answer:

padilas [110]4 years ago

7 0

Contact and non contact forces are big factors to consider in designing of different modes of transportation because this factors are resistances for the mode of transportation. These contact and non- contact forces should be minimized in order for the energy requirement to be also minimum. But not the extent of risking the safety, for example a non contact force is the wieght, the should be optimum, safety of the design should not be compromised just to reduce weight, just like by removing essential parts, support just to remove weight is not good.

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The skateboarder has a mass of 100 kg. When traveling downward from E to D, he reaches a velocity of 11 m/s. Calculate his kinet

patriot [66]

6050 J is the kinetic energy at D

<u>Explanation:</u>

In physics, the object's kinetic energy (K.E) defined as the energy it possesses during movement. It can be defined as the required work to accelerate a certain body weight in order to rest at a certain speed. When the body receives this energy as it speeds up (accelerates), it retains this energy unless speed varies. The equation is given as,

$K . E=\frac{1}{2} \times m \times v^{2}$

Where,

m - mass of an object

v - velocity of the object

Here,

Given data:

m = 100 kg

v = 11 m/s

By substituting the given values in the above equation, we get

$K . E=\frac{1}{2} \times 100 \times(11)^{2}=\frac{1}{2} \times 100 \times 121=\frac{12100}{2}=6050\ \mathrm{J}$

6 0

4 years ago

Which is the correct answer ?

hodyreva [135]

D ............................

7 0

4 years ago

Read 2 more answers

Anyone know how to do this ?

soldi70 [24.7K]

Not really but I need points lol

3 0

3 years ago

Read 2 more answers

slamgirl [31]

A is the correct answer: 100 degrees C is the boiling point of water, just subtract 82 from 100.

3 0

3 years ago

A 14.0 gauge copper wire of diameter 1.628 mmcarries a current of 14.0 mA. Part A: What is the potential difference across a 2.1

FrozenT [24]

Answer:

for copper potential difference is 2.4871 × $10^{-4}$ V

for silver potential difference is 2.1256 × $10^{-4}$ V

Explanation:

given data

diameter D = 1.628 mm = 0.001628 m

current = 14.0 mA = 0.0140 A

length L = 2.15 m

to find out

potential difference

solution

we consider here

resistivity of silver = 1.47 × $10^{-8}$ ohm-m

resistivity of copper = 1.72 × $10^{-8}$ ohm-m

so we apply here resistance formula that is

Resistance = ρ × L / A ...............1

so here area A = πr² = π(0.001628 /2)² = 2.0816 × $10^{-6}$ m²

for copper Resistance = ρ × L / A

Resistance = 1.72 × $10^{-8}$ × 2.15 / 2.0816 × $10^{-6}$

Resistance = 1.7765 × $10^{-2}$ ohm

for silver Resistance = ρ × L / A

Resistance = 1.47 × $10^{-8}$ × 2.15 / 2.0816 × $10^{-6}$

Resistance = 1.5183 × $10^{-2}$ ohm

so

potential difference is calculated as

for copper potential difference = current × resistance

potential difference = 0.0140 ×1.7765 × $10^{-2}$

potential difference = 2.4871 × $10^{-4}$ V

for silver potential difference = current × resistance

potential difference = 0.0140 × 1.5183 × $10^{-2}$

potential difference = 2.1256 × $10^{-4}$ V

7 0

3 years ago