What is the work done by a car's braking system when it slows the 1500-kg car from an initial speed of 96 km/h down to 56 km/h i
2 answers:
Answer:
-352.275KJ
Explanation:
We are given that
Mass of car=1500kg
Initial speed of car =u=96 km/h=
1km/h=
Final speed of car=v=56km/h=
Distance traveled by car=s=55m
We have to find the work done by the car's braking system.
Using third equation of motion
Where negative sign indicates that velocity of car decreases.
Work done by a car's barking system=
Work done by a car's barking system=
Work done by a car's barking system=
1KJ=1000J
Where negative sign indicates that work done in opposite direction of motion.
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Answer:
15.75 m
Explanation:
First, let's look at the top brick by itself. In order for it not to tip over the bottom brick, its center of gravity must be right at the edge of the bottom brick. So the edge of the top brick must be 10.5 m from the edge of the bottom brick.
Now let's look at both bricks as a combined mass. We know the total length of this combined brick is 10.5 m + 21 m = 31.5 m. And we know that for it to not tip over the edge of the surface, its center of gravity must be at the edge. So the edge of the combined brick must be 31.5 m / 2 = 15.75 m from the edge of the surface.
