What is the work done by a car's braking system when it slows the 1500-kg car from an initial speed of 96 km/h down to 56 km/h i
2 answers:
Answer:
-352.275KJ
Explanation:
We are given that
Mass of car=1500kg
Initial speed of car =u=96 km/h=
1km/h=
Final speed of car=v=56km/h=
Distance traveled by car=s=55m
We have to find the work done by the car's braking system.
Using third equation of motion
Where negative sign indicates that velocity of car decreases.
Work done by a car's barking system=
Work done by a car's barking system=
Work done by a car's barking system=
1KJ=1000J
Where negative sign indicates that work done in opposite direction of motion.
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Answer:
t = 16.5s
Explanation:
Given parameters:
Acceleration = 3.1m/s²
Initial velocity = 0m/s
Final velocity = 51m/s
Unknown:
Time taken = ?
Solution:
To solve this problem we need to reiterate that acceleration is the rate of change of velocity with time.
So;
Acceleration =
v is the final velocity
u is the initial velocity
t is the time taken
So;
3.1 =
3.1t = 51
t = 16.5s