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Angelina_Jolie [31]
3 years ago
14

What is the work done by a car's braking system when it slows the 1500-kg car from an initial speed of 96 km/h down to 56 km/h i

n a distance of 55 m?
Physics
2 answers:
kondor19780726 [428]3 years ago
7 0

Answer:

-352.275KJ

Explanation:

We are given that

Mass of car=1500kg

Initial speed of car =u=96 km/h=96\times \frac{5}{18}=26.67m/s

1km/h=\frac{5}{18}m/s

Final speed of car=v=56km/h=56\times \frac{5}{18}=15.56m/s

Distance traveled by car=s=55m

We have to find the work done by the car's braking system.

Using third equation of motion

v^2-u^2=2as

(15.56)^2-(26.67)^2=2a(55)

-469.18=110a

a=\frac{-469.18}{110}=-4.27m/s^2

Where negative sign indicates that velocity of car decreases.

Work done by a car's barking system=w=F\times s=ma\times s

Work done by a car's barking system=1500\times -4.27\times 55=352275J

Work done by a car's barking system=-\frac{352275}{1000}=-352.275KJ

1KJ=1000J

Where negative sign indicates that work done in opposite direction of motion.

Gennadij [26K]3 years ago
7 0

Answer:

Work done by the car's braking system W = 3.519×10^5 J

Explanation:

we can apply newton's equation of motion to find acceleration

as

apply v^2 -u^2 = 2as

v= final velocity

u= initial velocity

also 1 kmph = 5/18 m/s

v= 56×5/18= 15.6 m/s

u= 96×5/18 = 26.66 m/s

s= 55 m

so a = [(26.66)^2 -(15.4)^2]/2×55

a = 4.26 m/s^2

so F = ma

Mass m= 1500 kg

F = 1500×4.26

F = 6397.306 N

Now work done  W = F×s

W = 6397.306×55

W = 3.519×10^5 J

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The refractive index n of transparent acrylic plastic (full name Poly(methyl methacrylate)) depends on the color (wavelength) of
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Answer:

The angle between the blue beam and the red beam in the acrylic block is  

 \theta _d  =0.19 ^o

Explanation:

From the question we are told that

     The  refractive index of the transparent acrylic plastic for blue light is  n_F  =  1.497

     The  wavelength of the blue light is F  =  486.1 nm  =  486.1 *10^{-9} \ m

    The  refractive index of the transparent acrylic plastic for red light is  n_C  =  1.488

       The  wavelength of the red light is C =  656.3 nm  = 656.3 *10^{-9} \  m

    The incidence angle is  i  =  45^o

Generally from Snell's law the angle of refraction of the blue light  in the acrylic block  is mathematically represented as

       r_F =  sin ^{-1}[\frac{sin(i) *  n_a }{n_F} ]

Where  n_a is the refractive index of air which have a value ofn_a =  1

So

     r_F =  sin ^{-1}[\frac{sin(45) *  1 }{ 1.497} ]

      r_F  =  28.18^o

Generally from Snell's law the angle of refraction of the red light in the acrylic block is mathematically represented as

       r_C =  sin ^{-1}[\frac{sin(i) *  n_a }{n_C} ]

Where  n_a is the refractive index of air which have a value ofn_a =  1

So

     r_C =  sin ^{-1}[\frac{sin(45) *  1 }{ 1.488} ]

      r_F  =  28.37^o

The angle between the blue beam and the red beam in the acrylic block

     \theta _d  =  r_C  - r_F

substituting values

       \theta _d  = 28.37 -  28.18

       \theta _d  =0.19 ^o

 

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Answer:

Work done = 35467.278 J

Explanation:

Given:

Height of the cone = 4m

radius (r) of the cone = 1.2m

Density of the cone = 600kg/m³

Acceleration due to gravity, g = 9.8 m/s²

Now,

The total mass of the cone (m) = Density of the cone × volume of the cone

Volume of the cone = \frac{1}{3}\pi r^2 h

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volume of the cone = \frac{1}{3}\pi 1.2^2\times 4 = 6.03 m³

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The center of mass for the cone lies at the \frac{1}{4}times the total height

thus,

center of mass lies at,  h' = \frac{1}{4}\times4=1m

Now, the work gone (W) against gravity is given as:

W = mgh'

W = 3619.11kg × 9.8 m/s² × 1 = 35467.278 J

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