Answer:
3003 different groups of 6tops
Step-by-step explanation:
Using the combination formula, generally, when selecting r number of objects out of a pool of n numbers, this can be done in nCr number of ways.
nCr = n!/(n-r)!r!
If there are 14 tops I'd like to purchase and I can only afford six, the number of ways I can choose this six at random from the 14tops can be done in 14C6 number of ways.
14C6 = 14!/(14-6)!6!
14C6 = 14!/8!6!
14C6 = 14×13×12×11×10×9×8!/8!×6×5×4×3×2
14C6 = 14×13×12×11×10×9/6×5×4×3×2
14C6 = 14×13×12×11/8
14C6 = 3003ways
4,000,000,000 + 700,000,000 + 0 + 0 + 900,000 + 30,000 + 0 + 0 + 0 + 2
Let's pick an arbitrary value of 5.
Let's pick another arbitrary value: 1
Between these two values, the polynomial is continuous. This means for the two polynomial points to be satisfied, there must be
at least one root between these two points.
We can either use the Intermediate Value Theorem or Newton's method to make a better approximation from there.
The answer is the H graph.
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