What is 7+10x-2x-2=-3

1 answer:

6 0

7+10x-2x-2=-3

—-Combine like terms...10x-2x=8x and 7-2=5

8x+5=-3
——subtract 5 on both sides.. the 5’s will cancel each other and -3-5=-8

8x=-8
——Divide 8 on both sides...the 8’s will cancel out and -8 divided by 8 = -1

Answer: x = -1

You might be interested in

Solve for x 17-x=36 PLSSSS HELPPPPP (A. -53 (B. -19 (C. 19 (D. 53

Alisiya [41]

17 - x =36

subtract 17 on both sides

-x = 19

Now divide both sides by -1

Answer is B. -19

8 0

2 years ago

On a coordinate plane, a shape is plotted with vertices of (3, 1), (0, 4), (3, 7), and (6, 4). what is the area of the shape if

QveST [7]

Let
<span>A (3, 1)
B (0, 4)
C(3, 7)
D (6, 4)

step 1
find the distance AB
d=</span>√[(y2-y1)²+(x2-x1)²]------> dAB=√[(4-1)²+(0-3)²]-----> dAB=√18 cm

step 2
find the distance CD
d=√[(y2-y1)²+(x2-x1)²]------> dCD=√[(4-7)²+(6-3)²]-----> dCD=√18 cm

step 3
find the distance AD
d=√[(y2-y1)²+(x2-x1)²]------> dAD=√[(4-1)²+(6-3)²]-----> dAD=√18 cm

step 4
find the distance BC
d=√[(y2-y1)²+(x2-x1)²]------> dBC=√[(7-4)²+(3-0)²]-----> dBC=√18 cm

step 5
find slope AB and CD
m=(y2-y1)/(x2-x1)
mAB=-1
mCD=-1
AB and CD are parallel and AB=CD

step 6
find slope AD and BC
m=(y2-y1)/(x2-x1)
mAD=1
mBC=1
AD and BC are parallel and AD=BC
and
AB and AD are perpendicular
BC and CD are perpendicular

therefore
the shape is a square wit length side √18 cm

area of a square=b²
b is the length side of a square
area of a square=(√18)²------> 18 cm²

the answer is
18 cm²

see the attached figure