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Advocard [28]
3 years ago
5

Each of the 27 turtles in the pet store needs to be fed. There is one bag of turtle food that weighs 84 ounces. If each turtle g

ets the same amount of food, how many ounces of turtle food will each turtle get?
Mathematics
2 answers:
Anarel [89]3 years ago
3 0

Step-by-step explanation:

84 ounces / 27 turtles = 3.111 ounces per turtle

Or in fractional form, 3 ¹/₉ ounces per turtle.

sweet [91]3 years ago
3 0

Answer: the answer is 3.1 with the line on top of the 1

Step-by-step explanation:just took the test hope it is help full

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xxTIMURxx [149]
Y= 86 degrees and x= 47 degrees
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4 0
3 years ago
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Jackson will buy the items listed below. He has $422.76 in his checking account. He had a stored-valued card worth $75. He withd
Inessa05 [86]

Answer:

A

Step-by-step explanation:

44.99+299.49 = $344.38

$344.38 - store card ($75) = $269.48

422.76 - 269.48 - 2.5 = $150.78

Therefore answer is A

6 0
3 years ago
A club raises $3,207 to buy stuffed animals for a local children's hospital. Each stuffed animal costs $17. What is the maximum
Ksju [112]

Answering:

188

Explaining:

To solve this problem, we must divide the total amount of money raised by the cost of the stuffed animals. Each stuffed animal costs $17. The club raised $3,207 to buy said stuffed animals. By dividing the money earned, which is also the money the club is able to spend, by the cost of a single/one stuffed animal, we will get how many stuffed animals the club can purchase with the money they currently possess. Our equation will look like this: 3,207 ÷ 17.

After dividing 3,207 by 17, we have the number 188.64705882. This can be rounded to the nearest tenth to create the simpler yet still accurate number 188.6.

Our final step is to round 188.6 down to the whole number it already has. (That is to say, simply cut off the fraction and remove it to get our answer.) This step must be done because we are buying stuffed animals in a real-world situation. The club would not be able to purchase part of a stuffed animal for a fraction of the cost, and the cost of the stuffed animals in the problem is a fixed value. This means that the fraction is irrelevant since we cannot purchase anything with it, effectively making it totally irrelevant to the answer. After removing the fraction from 188.6, we are left with 188.

Therefore, the maximum number of stuffed animals the club can buy is <em>188 stuffed animals</em>.

4 0
3 years ago
Find the 19th term of the arithmetic sequence whose common difference is =d5 and whose first term is =a12.
emmasim [6.3K]
An=a1+d(n-1)
a1=first term
d=common difference
n=which term

common difference is 5 first term is 2
an=5+2(n-1)
19th term is n=19
a19=5+2(19-1)
a19=5+2(18)
a19=5+36
a19=41

19th term is 41
4 0
3 years ago
Consider the following set of equations, where s, s0, x and r have units of length, t has units of time, v has units of velocity
Anna11 [10]

Answer:

5

Step-by-step explanation:

For an equation to be dimensionally correct the dimension of quantities on both sides of equation must be same.

Also, two physically quantities can only be added or subtracted only when their dimension are same.

here all option are dimensionally correct except the 5th option where

dimension of t= [T] whereas dimension of a/v is \frac{LT^{-2}}{LT^{-1}}

= T^{-1}

since, the dimension of quantities on either sides of equation are not the same the equation is dimensionally is incorrect.

8 0
3 years ago
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