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Vinvika [58]
2 years ago
7

The rate of change of the volume of a snowball that is melting is proportional to the surface area of the snowball. Suppose the

snowball is perfectly spherical. Then the volume (in centimeters cubed) of a ball of radius r centimeters is 4/3πr3. The surface area is 4πr2. Set up the differential equation for how r is changing. Then, suppose that at time t = 0 minutes, the radius is 10 centimeters. After 5 minutes, the radius is 8 centimeters. At what time t will the snowball be completely melted.
Mathematics
1 answer:
Alisiya [41]2 years ago
6 0

Answer:

According to the passage, we have the next equation:

\frac{dV}{dt} = \frac{4}{3}\pi*3*r^{2}*\frac{dr}{dt} = K*(4\pi*r^{2} )

where "K" is a proportional constant

Leaving at the end with the next equation:

\frac{dr}{dt} = K

Integrating the equation, we have:

r=K*t+C

where "C" is a constant

Then, we have the 2 conditions for the problem:

1) t=0 → r=10

Replacing in the equation, we have C = 10

2) t=5 → r=8

Replacing in the equation, we have K = -0.4

Finally, the time which the snowball will be completely melted will be when r = 0. So replacing in the equation

0=-0.4*t+10

t = 25 minutes

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