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Minchanka [31]
3 years ago
11

Please help i really appreciate it

Mathematics
1 answer:
mars1129 [50]3 years ago
8 0

Answer:

C

Step-by-step explanation:

i litterally just did this question i believe

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Not a hard question i just don't get it. I really need some help here, its the final
Greeley [361]

Start with

\dfrac{1}{\sin^2(x)}=4

Invert both sides:

\sin^2(x) = \dfrac{1}{4}

Consider the square root of both sides with double sign:

\sin(x) = \pm\sqrt{\dfrac{1}{4}} = \pm\dfrac{1}{2}

We have

\sin(x) = \dfrac{1}{2} \iff x = \dfrac{\pi}{6}\ \lor\ x = \dfrac{5\pi}{6}

and

\sin(x) = -\dfrac{1}{2} \iff x = \dfrac{7\pi}{6}\ \lor\ x = \dfrac{11\pi}{6}

5 0
3 years ago
Devin buys 12 candy bars for
wolverine [178]
Devin is buying 12 for $12 so for each he bought it was $1. If he’s selling them for the same price he bought them for (each) when he sells all 12 for $1, he will be left off with the same price he started off with. Devin is not making any profit. What i would do is sell them for $1.50, and then after each is sold, the total earnings would be $18.
8 0
3 years ago
the length of a rectangle is 7 yd more than 5 times the width. the perimeter is 150 yd. find the length and the width.
Vaselesa [24]
P = 2(L + W)
P = 150
L = 5W + 7

150 = 2(5W + 7 + W)
150 = 2(6W + 7)
150 = 12W + 14
150 - 14 = 12W
136 = 12W
136/12 = W
11.33 (or 11 1/3) = W <=== width

L = 5W + 7
L = 5(34/3) + 7
L = 170/3 + 7
L = 170/3 + 21/3
L = 191/3 (or 63 2/3) = L <=== length
4 0
3 years ago
Solve<br>4(2x - 3) = 6x + 2​
vaieri [72.5K]

。☆✼★ ━━━━━━━━━━━━━━  ☾  

4(2x - 3) = 6x + 2

Expand it:

8x - 12 = 6x + 2

+ 12 to both sides

8x = 6x + 14

- 6x from both sides

2x = 14

Divide both sides by  2:

x = 7

Have A Nice Day ❤    

Stay Brainly! ヅ    

- Ally ✧    

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4 0
3 years ago
Multiply the polynomials show steps
Karo-lina-s [1.5K]

Answer:

3a^{4} + 11a³ - 7a² + 18a - 18

Step-by-step explanation:

<u>When multiplying with two brackets, you need to multiply the three terms, (a²), (4a) and (-6) from the first bracket to all the terms in the second brackets, (3a²), (-a) and (3) individually. I have put each multiplied term in a bracket so it is easier.</u>

(a² + 4a - 6) × (3a² - a + 3) =

(a² × <em>3a²</em>) + {a² × <em>(-a)</em>} + (a² × <em>3</em>) + (4a × <em>3a²</em>) + {4a × <em>(-a)</em>} + (4a × <em>3</em>) + {(-6) × <em>a²</em>) + {(-6) × <em>(-a)</em>} + {(-6) × <em>3</em>}

<u>Now we can evaluate the terms in the brackets. </u>

(a² × 3a²) + {a² × (-a)} + (a² × 3) + (4a × 3a²) + {4a × (-a)} + (4a × 3) + {(-6) × a²) + {(-6) × (-a)} + {(-6) × 3} =

3a^{4} + (-a³) + 3a² + 12a³ + (-4a²) + 12a + (-6a²) + 6a + (-18)

<u>We can open the brackets now. One plus and one minus makes a minus. </u>

3a^{4} + (-a³) + 3a² + 12a³ + (-4a²) + 12a + (-6a²) + 6a + (-18) =

3a^{4} -a³ + 3a² + 12a³ -4a² + 12a -6a² + 6a -18

<u>Evaluate like terms.</u>

3a^{4} -a³ + 3a² + 12a³ -4a² + 12a -6a² + 6a -18 = 3a^{4} + 11a³ - 7a² + 18a - 18

5 0
3 years ago
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