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Dominik [7]
2 years ago
10

Which of the two circles in this figure is larger? A Shape and Lines

Mathematics
1 answer:
faltersainse [42]2 years ago
6 0

Answer: Shapes

Step-by-step explanation: Lines is simple and soft, Shapes is sharp and hard

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Keith_Richards [23]

Answer:

one second

Step-by-step explanation:

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3 years ago
Given f(x)= -4x-10 and f(x)=10. find x
yulyashka [42]

Answer:

x = - 5

Step-by-step explanation:

Given

f(x) = - 4x - 10 and f(x) = 10, the equate right sides, that is

- 4x - 10 = 10 ( add 10 to both sides )

- 4x = 20 ( divide both sides by - 4 )

x = - 5

4 0
3 years ago
You are paid 3.50 for every case you deliver to a store. If you deliver fifty seven cases, what will you be paid for that delive
Stels [109]

Answer:

199.50

Step-by-step explanation:

Given the 3.50 payment for every case delivered to a store:

This means that you will earn 199.50 for delivering 57 cases, because:

57 cases × 3.50 each case = 199.50

Therefore, you will be paid 199.50 for that delivery.

3 0
2 years ago
Read 2 more answers
What is the value of n in the equation ? n = 0 n = 2 n = 4 n = 6
RideAnS [48]

Answer:

N=2

Step-by-step explanation:

N=2

5 0
3 years ago
Read 2 more answers
The coordinates of rhombus ABCD are A(–4, –2), B(–2, 6), C(6, 8), and D(4, 0). What is the area of the rhombus? Round to the nea
a_sh-v [17]
Check the picture below.

so the rhombus has the diagonals of AC and BD, now keeping in mind that the diagonals bisect each, namely they cut each other in two equal halves, let's find the length of each.

\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
A(\stackrel{x_1}{-4}~,~\stackrel{y_1}{-2})\qquad 
C(\stackrel{x_2}{6}~,~\stackrel{y_2}{8})\qquad \qquad 
%  distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
AC=\sqrt{[6-(-4)]^2+[8-(-2)]^2}\implies AC=\sqrt{(6+4)^2+(8+2)^2}
\\\\\\
AC=\sqrt{10^2+10^2}\implies AC=\sqrt{10^2(2)}\implies \boxed{AC=10\sqrt{2}}\\\\
-------------------------------

\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
B(\stackrel{x_1}{-2}~,~\stackrel{y_1}{6})\qquad 
D(\stackrel{x_2}{4}~,~\stackrel{y_2}{0})\qquad \qquad BD=\sqrt{[4-(-2)]^2+[0-6]^2}
\\\\\\
BD=\sqrt{(4+2)^2+(-6)^2}\implies BD=\sqrt{6^2+6^2}
\\\\\\
BD=\sqrt{6^2(2)}\implies \boxed{BD=6\sqrt{2}}

that simply means that each triangle has a side that is half of 10√2 and another side that's half of 6√2.

namely, each triangle has a "base" of 3√2, and a "height" of 5√2, keeping in mind that all triangles are congruent, then their area is,

\bf \stackrel{\textit{area of the four congruent triangles}}{4\left[ \cfrac{1}{2}(3\sqrt{2})(5\sqrt{2}) \right]\implies 4\left[ \cfrac{1}{2}(15\cdot (\sqrt{2})^2) \right]}\implies 4\left[ \cfrac{1}{2}(15\cdot 2) \right]
\\\\\\
4[15]\implies 60

7 0
2 years ago
Read 2 more answers
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