First subtract 2 revolutions from the - 840 :- (- (840-720) = -120
This gives sin -120 which is in the 3rd quadrant of the unit circle
sin -120 = - sin 60 = - sqrt3/2
First lets see the pythagorean identities

So if we have to solve for sin theta , first we move cos theta to left side and then take square root to both sides, that is

Now we need to check the sign of sin theta
First we have to remember the sign of sin, cos , tan in the quadrants. In first quadrant , all are positive. In second quadrant, only sin and cosine are positive. In third quadrant , only tan and cot are positive and in the last quadrant , only cos and sec are positive.
So if theta is in second quadrant, then we have to positive sign but if theta is in third or fourth quadrant, then we have to use negative sign .
Answer:
Dotted linear inequality shaded above passes through (0, 4) and (4, 0). Solid exponential inequality shaded below passes through (negative 2,2) & (0,5)
Step-by-step explanation:
we have
----> inequality A
The solution of the inequality A is the shaded area above the dotted line 
The dotted line passes through the points (0,4) and (4,0) (y and x-intercepts)
and
-----> inequality B
The solution of the inequality B is the shaded area above the solid line 
The solid line passes through the points (0,5) and (-2,2)
therefore
The solution of the system of inequalities is the shaded area between the dotted line and the solid line
see the attached figure
Dotted linear inequality shaded above passes through (0, 4) and (4, 0). Solid exponential inequality shaded below passes through (negative 2,2) & (0,5)
Answer:
45min
Step-by-step explanation:
just mutiply