Answer: 4.6 is the answer to 1.38 divided by 0.3=4.6
1
P(V|A) is not 0.95. It is opposite:
P(A|V)=0.95
From the text we can also conclude, that
P(A|∼V)=0.1
P(B|V)=0.9
P(B|∼V)=0.05
P(V)=0.01
P(∼V)=0.99
What you need to calculate and compare is P(V|A) and P(V|B)
P(V∩A)=P(A)⋅P(V|A)⇒P(V|A)=P(V∩A)P(A)
P(V∩A) means, that Joe has a virus and it is detected, so
P(V∩A)=P(V)⋅P(A|V)=0.01⋅0.95=0.0095
P(A) is sum of two options: "Joe has virus and it is detected" and "Joe has no virus, but it was mistakenly detected", therefore:
P(A)=P(V)⋅P(A|V)+P(∼V)⋅P(A|∼V)=0.01⋅0.95+0.99⋅0.1=0.1085
Answer:
The other answer is INCORRECT the CORRECT answer is : 34.00
Step-by-step explanation:
In the chart it shows how much for the number of exemptions. The other answer only included one but the question asks for TWO. Therefore making it 34.00
Answer:
The answer is below
Step-by-step explanation:
When you refer to a normal vector you mean the form a*x + b*y + c*z = d, if that's the case then it's not unique in the nose because it gives you its normal vector. Taking into account that uniqueness only supports multiplicative constants, which means that you can multiply the equation with whatever you want, that is, it remains the same
Answer:
In the explanation
Step-by-step explanation:
x = 0, y = -2*0+11=11
x = 1, y = -2*1+11=9
x = 4, y = -2*4+11=3
Hope this helps!
