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3 years ago

What 76 rounded to the nearest 10

2 answers:

8 0

76 rounded to the nearest 10th is 80
if the number is a 5 or above in the second number it goes up to the next number with a 0 if its 4 or under is goes to the lower number with a 0

Kisachek [45]3 years ago

5 0

76 rounded to the nearest 10 is 80.

Since 6 is greater than 5, it rounds 7 to 8.

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Find the mode for the scores 3,760, 5,200, 8,750, 4,400, 5,250

Semenov [28]

There is no mode in these scores.

This is because mode is when two numbers show up the same like 4 and 4.

8 0

2 years ago

A drawing contains 5 circles, 8 triangles, and 6 squares. What is the ratio of triangles to circles? Write the ratio using a fra

zavuch27 [327]

Answer:

8:5 or 8/5

Step-by-step explanation:

4 0

2 years ago

Plz help asap will markbrainliest

kicyunya [14]

This is called a Supplementary Angle, meaning the angles MUST add up to 180 Degree.

Angle 1 will be 94 (94-18 = 76).

Angle 2 will be 13 (8x13 = 104).

(Please mark this as the brainliest if this helps!)

7 0

3 years ago

Read 2 more answers

Find the area of the circle. Use 3.14 for π. d = 10 cm A = [?] cm² A=TCr2

Stells [14]

Answer:

78.5

Step-by-step explanation:

The diameter (d) is equal to the radius x 2, so take half of d to get r. Use r (5) in the equation to get your answer.

A= 3.12 x 5^2

A= 78.5

5 0

2 years ago

The service life of a battery used in a cardiac pacemaker is assumed to be normally distributed. A random sample of ten batterie

Fittoniya [83]

Answer:

The confidence interval is $25.16 < \mu < 26.85$

Step-by-step explanation:

From the question we are given a data set

25.5, 26.1, 26.8, 23.2, 24.2, 28.4, 25.0, 27.8, 27.3, and 25.7.

The mean of the this sample data is

$\= x = \frac{\sum x_i}{n}$

where is the sample size with values n = 10

$\= x = \frac{25.5+ 26.1+ 26.8+23.2+ 24.2+ 28.4+ 25.0+ 27.8+ 27.3+ 25.7}{10}$

$\= x = 26$

The standard deviation is evaluated as

$\sigma = \sqrt{\frac{\sum (x-\= x)}{n} }$

substituting values

$= \sqrt{\frac{ ( 25.5-26)^2, (26.1-26)^2, (26.8-26)^2, (23.2-26)^2}{10} }$

$\cdot \ \cdot \ \cdot \sqrt{\frac{ ( 24.2-26)^2, (28.4-26)^2+( 25.0-26)^2+ (27.8-26)^2+( 27.3-26)^2+( 25.7-26)^2}{10} }$

$\sigma = 1.625$

The confidence level is given as 90% hence the level of significance is calculated as

$\alpha = 100 -90$

$\alpha =10$ %

$\alpha = 0.10$

Now the critical values of $\frac{\alpha }{2}$ is obtained from the normal distribution table as

$Z_{\frac{\alpha }{2} } = 1.645$

The reason we are obtaining the critical values of $\frac{\alpha }{2}$ instead of $\alpha$ is because we are considering two tails of the area under the normal curve