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Goryan [66]
3 years ago
9

What are the possible numbers of positive, negative, and complex zeros of f(x)=x^6-x^5-x^4+4x^3-12x^2+12?

Mathematics
1 answer:
Vadim26 [7]3 years ago
8 0
f(x)=x^6-x^5-x^4+4x^3-12x^2+12\\\\12:\{\pm1;\ \pm2;\ \pm3;\ \pm4;\ \pm6;\ \pm12\}\\1:\{\pm1\}\\\\Answer:\boxed{\{\pm1;\ \pm2;\ \pm3;\ \pm4;\ \pm6;\ \pm12\}}
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Find the magnitude of WX for W(-2, 8, -3) and X(1, 4, -1)
zheka24 [161]

The magnitude of WX is  \sqrt{29}  ⇒ c

Step-by-step explanation:

The magnitude of XY (its length) where,

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is IXYI = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}+(z_{2}-z_{1})^{2}}

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∴ x_{1} = -2 and x_{2} = 1

∴ y_{1} = 8 and y_{2} = 4

∴ z_{1} = -3 and z_{2] = -1

- Substitute these values in the rule above

∵ IWXI = \sqrt{(1--2)^{2}+(4-8)^{2}+(-1--3)^{2}}=\sqrt{9+16+4}

∴ IWXI = \sqrt{29}

The magnitude of WX is  \sqrt{29}

Learn more:

You can learn more about the position of an object in brainly.com/question/10940255

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3 years ago
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Broken down into steps:

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