Answer:
Option c. The distributions of weight loss of the two treatments are approximately normally distributed.
Step-by-step explanation:
To increase the confidence level, the results must be able to satisfy the following conditions:
- The sample size is increased. This reduces the margin of the error in the sampling experiment.
- Reduction of the variability. This means that the less the data varies, the more precise the data is.
- Using the one-sided confidence level
- Lowering the confidence level.
All these characteristics can only be satisfied by the normal distribution curve.
Answer:
R theta 1 = 20 x
R theta 2 = 11 x - 6
R ( theta 1 + theta 2) = 31 x - 6 adding equations
R pi = 31 x - 6 since theta 1 + theta 2 = 180 deg
x = (R pi + 6) / 31
This equation depends only R
If one lets R be one then x = (pi + 6) / 31
This would give x = .29489 rad for the value of pi is deg
The numerical value of x appears to depend on the value of R
If cats like playing with mice then they will chase them
Answer:
a. Short-Sleeve = 35
b. Long-Sleeve = 27
Step-by-step explanation:
Given data:
Total shirts sold = 62
short sleeved cost = 11 each
Long sleeved cost = 17 each
Total receipts = 844
<em>Let the count of short sleeved be X and Let the count of long sleeved be Y</em>
X + Y = 62 <em>(equation 1) from the total shirts sold</em>
11X + 17Y = 844 <em>(equation 2) from the total receipts</em>
<em>From equation 1</em> X = 62 - Y <em>(Equation 3)</em>
<em>Substituting equation 3 into equation 2</em>
11(62 - Y) +17Y = 844
682 -11Y + 17Y = 844
-11Y + 17Y = 844-682
6Y = 162
Therefore Y = 27
<em>Substituting Y into equation 3</em>
X = 62 - Y
X = 62 - 27
X = 35
