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3 years ago

If the point C is located at (5, 4) and C' is the image of C after being translated right 2. What are the

Mathematics

1 answer:

slega [8]3 years ago

8 0

Answer:

(7, 4)

Step-by-step explanation:

If point C is being translated to the right 2, the x coordinate will increase by 2. But, the y coordinate will stay the same.

Find the coordinates of C' by adding 2 to the original x coordinate:

5 + 2 = 7

The y coordinate will still be 4.

So, the coordinates of C' will be (7, 4)

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Rus_ich [418]

$363.9ft^{2}$

Step-by-step explanation:

$Area =\pi r^{2} -\frac{1}{3}\pi r^{2} +\frac{1}{2}r^{2}sin\alpha \\\\\\ = \frac{2}{3}\pi 12^{2} +\frac{1}{2}12^{2}sin120 =363.9ft^{2}$

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3 years ago

Read 2 more answers

Imagine the center of the Singapore Flyer ferris wheel is located at (0, 0) on a coordinate grid, and the radius lies on the x-a

stealth61 [152]

The equation of the circle is x² + y² = 25 and the transformation equation of the circle is x² + y² = 100.

<h3>What is the equation of the circle?</h3>

The following parameters are derived from the question:

(x - a)² + (y - b)² = r²

Center (a, b) = (0, 0)

Radius (r) = 5

Then the equation of the circle will be

x² + y² = 5²

x² + y² = 25

Then the transformation of the circle will be

Center (a, b) = (0, 0)

Radius (r) = 10

Then the equation of the circle will be

x² + y² = 10²

x² + y² = 100

More about the equation of circle link is given below.

brainly.com/question/10618691

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2 years ago

You estimated the average rental cost of a 2 bedroom apartment in Denton. A random sample of 16 apartments was taken. The sample

Zigmanuir [339]

Answer:

The new sample size required in order to have the same confidence 95% and reduce the margin of erro to $60 is:

n=28

Step-by-step explanation:

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Assuming the X follows a normal distribution

$X \sim N(\mu, \sigma=160)$

And the distribution for $\bar X$ is:

$\bar X \sim N(\mu, \frac{160}{\sqrt{n}})$

We know that the margin of error for a confidence interval is given by:

$Me=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The next step would be find the value of $\z_{\alpha/2}$ , $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$

Using the normal standard table, excel or a calculator we see that:

$z_{\alpha/2}=\pm 1.96$

If we solve for n from formula (1) we got:

$\sqrt{n}=\frac{z_{\alpha/2} \sigma}{Me}$

$n=(\frac{z_{\alpha/2} \sigma}{Me})^2$

And we have everything to replace into the formula:

$n=(\frac{1.96(160)}{78.4})^2 =16$

And this value agrees with the sample size given.

For the case of the problem we ar einterested on Me= $60, and we need to find the new sample size required to mantain the confidence level at 95%. We know that n is given by this formula:

$n=(\frac{z_{\alpha/2} \sigma}{Me})^2$

And now we can replace the new value of Me and see what we got, like this:

$n=(\frac{1.96*160}{60})^2 =27.32$