Answer:
36.7 ft
Step-by-step explanation:
Measurements for the sides of the canal is given as: 40 ft. and 16 ft.
You solve the above question using Pythagoras Theorem
The distance across the canal is calculated as:
√(40² - 16²)
= √(1344)
= 36.66060556 ft
Approximately = 36.7 ft
Therefore, the distance x across the canal = 36.7 ft
For this case we must find the value of the variable "x" of the following equation:
We multiply by 3 on both sides of the equation:
We divide between 2 on both sides of the equation:
We subtract 7 on both sides of the equation:
Answer:
Option B
To find the surface area you will need to find the area of all 5 surfaces (faces) on the prism. On a triangular prism there are 2 triangular faces and 3 rectangular faces. All 3 rectangular faces are the same and the 2 triangular faces are also the same.
To find the area of the triangular faces, you will use the formula for finding the area of a triangle:
A = 1/2bh
1/2 x 10 x 8.7
A = 43.5 in^2
To find the area of the rectangular faces, you will use the formula for finding the area of a rectangle:
A = bh
10 x 3
A = 30 in ^2
30 + 30 + 30 + 43.5 + 43.5 = 177
The minimum amount of wrapping paper needed for the gift is 177 square inches.
Answer: <em>m = 7</em>
Step-by-step explanation: In this equation, since a -5 is being multiplied by <em>m</em>, in order to get <em>m</em> by itself, we must divide both sides of the equation by -5.
On the left side, our -5's cancel out and we are left with <em>m</em>. On the right side, -35 ÷ -5 gives us 7. So m = 7.
To check our answer, we plug 7 back in for <em>m</em> in the original equation and we get -5 (7) = -35 which is a true statement so we know our answer is correct.
Don't just do this problem in your head. It's extremely important to develop the habit of putting all your steps down on paper or digitally. It will really pay off for you down the line.
Answer:
d
Step-by-step explanation:
Δ OPG is right with hypotenuse OG being the radius of the circle
Using Pythagoras' identity in the right triangle
OG² = OP² + PG²
[ PG = 11 , since OP is the perpendicular bisector of FG ]
OG² = 8² + 11² = 64 + 121 = 185
Δ OQS is right with hypotenuse OS being the radius
Using Pythagoras' identity
OS² = QS² + OQ² , that is
185 = 13² + x²
185 = 169 + x² ( subtract 169 from both sides )
16 = x² ( take the square root of both sides )
4 = x → d
