Answer:
x = (7,0)
y = (0,1)
Step-by-step explanation:
Answer:
θ = 60° or θ = 120°, which in radians is equivalent to θ = π/3 rad or θ = 2π/3 rad.
Explanation:
The given equation is sin θ = (√3)/2
Solving that equation is finding the value of the angle, θ, whose sine is (√3)/2.
The function that returns the value of the angle whose sine is (√3)/2 is the inverse function of the sine and it has a special name: arc sine or arcsin.
Hence, θ = arcsin (√3)/2.
You can use your knowledge of the notable angles to solve for that equation.
1) The function sine is positive in first and second quadrants.
2) The angles in the first quadrant go from 0° to 90°.
3) The sine of 60° (√3)/2, Hence the first value of θ is 60°
4) The angles in the second quatrant go from 90° to 120°. 60° is the reference angle in the second quadrant, and the angle searched is
- 180° - reference angle = 180° - 60° = 120°. So, 120° is the other solution of the equation.
5) You can convert both angles to radians using the equivalence
- π radians = 180° ⇒ 1 = π rad / 180°
- 60° = 60° × π rad / 180° = π/ 3 rad
- 120° = 120° × π rad / 180° = 2π/3 rad
6) You can verify that sin 60° = (√3)/2 = sin 120° .
Alright, lets get started.
Suppose the speed to the ranch = x mph
So, speed to the ocean will be = (x-4) mph (because the speed was 4 mph less than the speed to the ranch)
Distance to the ranch = 888 miles
time moving to the ranch 
time moving to the ranch 
time moving to the ocean 
As per given in question, the 888 mile trip to the ranch took three times as long as the 280 mile trip to the ocean , means


Corss multiplying




Hence speed to ranch = 74 mph
Hence speed to ocean =
mph
time for trip to ranch =
hrs
time for trip to ocean =
hrs
So, speed to ranch is 74 mph and trip time is 12 hrs and speed to ocean is 70mph and time is 4 hrs.
Hope it will help :)
Answer: 6 hours
Step-by-step explanation:
Let x= the number of hours they've worked
12x+6x=108
Combine like terms
18x=108
Divide 18 on both sides
18/18 x=108/18
x=6
Hope this helps!! :)
Please let me know if you have any question
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