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3 years ago

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What is domain and range

1 answer:

4vir4ik [10]3 years ago

6 0

Answer:

Domain is the values of x within the function and y is the values of y within the function. They are the defined values for x, and y respectively, where the function results in a function. For any function, the domain is the input value and the range is the output values.

Hope this helps :)

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help please!! i have 20 minutes left to do this and I don't get the rest :( please answer the 3 of them !!

bonufazy [111]

Answer:

1st question answer is 10cm2

2nd question answer is 1368 in2

3rd question answer is 45 in2

Step-by-step explanation:

1st question explanation is 16+ 24 = 40

2nd question explanation is 19 x 8 x 9 = 1368

3rd question explanation is 8 x 2 1/4 x 2 1/2 = 45

DON'T COMPLAIN IF WRONG!

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Semenov [28]

Answer:

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Step-by-step explanation:

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A box of laundry detergent contains 35cups. It takes 1 1/4 cups per load of laundry

Dahasolnce [82]

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3 years ago

1 + 1? <br> .......……………………

masya89 [10]

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Ten engineering schools in the United States were surveyed. The sample contained 250 electrical engineers, 80 being women; 175 c

steposvetlana [31]

Answer:

There is a significant difference between the two proportions.

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for difference between population proportions is:

$CI=(\hat p_{1}-\hat p_{2})\pm z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})}{n_{1}}+\frac{\hat p_{2}(1-\hat p_{2})}{n_{2}}}$

Compute the sample proportions as follows:

$\hat p_{1}=\frac{80}{250}=0.32\\\\\hat p_{2}=\frac{40}{175}=0.23$

The critical value of <em>z</em> for 90% confidence interval is:

$z_{0.10/2}=z_{0.05}=1.645$

Compute a 90% confidence interval for the difference between the proportions of women in these two fields of engineering as follows:

$CI=(\hat p_{1}-\hat p_{2})\pm z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})}{n_{1}}+\frac{\hat p_{2}(1-\hat p_{2})}{n_{2}}}$

$=(0.32-0.23)\pm 1.645\times\sqrt{\frac{0.32(1-0.32)}{250}+\frac{0.23(1-0.23)}{175}}\\\\=0.09\pm 0.0714\\\\=(0.0186, 0.1614)\\\\\approx (0.02, 0.16)$

There will be no difference between the two proportions if the 90% confidence interval consists of 0.

But the 90% confidence interval does not consists of 0.

Thus, there is a significant difference between the two proportions.

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3 years ago