Well, the last digit in the product will only come from the last digits of the numbers that you're multiplying together. So for 0.303 & 4.48, that last digits are 3 & 8 so that last digit in the product would come from
![3 \times 8 = 24](https://tex.z-dn.net/?f=3%20%5Ctimes%208%20%3D%2024)
So 4. There are only two options that end in 4, 1.35744 & 0.13574. You can by the magnitude of the numbers that it isn't as small as 0.13574 so the answer must be 1.35744.
Answer: is 6 because if you take away 32 and 14 you will get 18 and if you divide 18 into 3 equal piles for three days you will get 6.......graded assignments
Your Welcome:)
A=1 b=8 c=8
h = [-8 +-sq root(64 - 4*1*8)] / 2
h = [-8 +-sq root(32)] / 2
h1 = -4 +
<span>
<span>
<span>
2.8284271247
</span>
</span>
</span>
h1 =
<span>
<span>
<span>
-1.1715728753
</span>
</span>
</span>
h2 = -4 -
<span>
<span>
2.8284271247
</span></span>h2 = -<span> 6.8284271247
</span>
Answer:
(3 and 15)
Step-by-step explanation:
If the product of both of these two numbers needs to be a negative 45 then there are no pair of integers that comply with both requirements.
If the multiplication in the question is wrong and it is a positive 45 then the pair of integers that would comply with these requirements would be (3 and 15). Multiplying this pair together would give you 45 and the difference between them is also 12 meaning it complies with both requirements that were asked for in the question.
Answer:
68/99
Step-by-step explanation:
.68686868686 repeating
Let x= .68686868668repeating
Multiply by 100
100x = 68.686868686repeating
Subtract x = .68686868repeating from this equation
100x = 68.686868686repeating
-x = .68686868repeating
------------------------------------------
99x = 68
Divide each side by 99
99x / 99 = 68/99
x = 68/99