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bixtya [17]
3 years ago
14

X + 2y = -3 x - y = -12

Mathematics
2 answers:
Nastasia [14]3 years ago
5 0

Answer:

x = -9, y =3

Step-by-step explanation:

x + 2y = -3

x - y = -12

Subtract to two equations to eliminate x

x + 2y = -3

-x + y = 12

---------------------

   3y = 9

Divide each side by 3

3y/3 = 9/3

y = 3

Now we can find x

x-y =-12

x - 3 = -12

Add 3 to each side

x-3+3 = -12+3

x = -9

Sunny_sXe [5.5K]3 years ago
5 0

Answer:

(-9,3)

Step-by-step explanation:

x + 2y = -3

x = -3 - 2y

x - y = -12

x = y - 12

-3 - 2y = y - 12

3y = 9

y = 3

x = 3 - 12

x = -9

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Sav [38]

Answer:

68.26% probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 7.5, \sigma = 1.1

What is the probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds

This is the pvalue of Z when X = 8.6 subtracted by the pvalue of Z when X = 6.4. So

X = 8.6

Z = \frac{X - \mu}{\sigma}

Z = \frac{8.6 - 7.5}{1.1}

Z = 1

Z = 1 has a pvalue of 0.8413

X = 6.4

Z = \frac{X - \mu}{\sigma}

Z = \frac{6.4 - 7.5}{1.1}

Z = -1

Z = -1 has a pvalue of 0.1587

0.8413 - 0.1587 = 0.6826

68.26% probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds

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3 years ago
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