You substitute M for 3 and C for 6. So you get E = (3)(6)(2) which equals 36.
Answer:
AC = BC = 5
AB = 5√2
∠A = ∠B = 45
∠A = 90
Step-by-step explanation:
AC = 5 ( Reason : 5 squares are present in between A and C )
Similarly,
BC = 5
<u>By Pythagoras theorem</u>,
(AB)² = (AC)² + (BC)²
= 5² + 5²
= 2 * 5²
(AB)² = 2 * 5²
AB = 5√2
Since, sides AC and BC are equal,
∠A = ∠B = 45
Since, AC is perpendicular to BC,
∠A = 90
So lets try to prove it,
So let's consider the function f(x) = x^2.
Since f(x) is a polynomial, then it is continuous on the interval (- infinity, + infinity).
Using the Intermediate Value Theorem,
it would be enough to show that at some point a f(x) is less than 2 and at some point b f(x) is greater than 2. For example, let a = 0 and b = 3.
Therefore, f(0) = 0, which is less than 2, and f(3) = 9, which is greater than 2. Applying IVT to f(x) = x^2 on the interval [0,3}.
Learn more about Intermediate Value Theorem on:
brainly.com/question/11377865
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X=6 is the answer to your question
