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2 years ago

Write the following in slope-intercept form , when the slope is -4 and the y-intercept is 9

Mathematics

1 answer:

Lera25 [3.4K]2 years ago

6 0

Answer:

y= -4x+9

Step-by-step explanation:

y=mx+b

mx= slope

b= y-intercept

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How many ways can a president, vice president, and secretary be selected from a class of 30 students? a. 90 b. 2,068 c. 4,060 d.

Ad libitum [116K]

Answer:

the answer to your question should be 2,068

Step-by-step explanation:

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2 years ago

Find the slope between the points (0,8) and (4,4)

Oxana [17]

Answer:

Slope=-1

Step-by-step explanation:

Slope=y1-y2/x1-x2

Where (X1,y1)(0,8) and (X2,y2) (4,4)

Slope=8-4/0-4

=4/-4

=-1

So slope is -1

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2 years ago

I will mark u brainliest please help

musickatia [10]

Answer:

30+(2x+7)+63=180(sum of angles of triangle )

30+2x+7+63=180

2x+100=180

2x=180-100

x=80/2

x=40

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2 years ago

Read 2 more answers

dog brought a new jet ski for $299 down in 14 monthly payments are $57 how much did Doug pay for the jet ski total

Effectus [21]

If he paid $57 monthly for 14 months, the total amount paid is:

$57\times14=798$

He paid $798 in total

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6 months ago

1. Write the form of the partial fraction decomposition of the rational expression. Do not solve for the constants.

german

Answer:

Step-by-step explanation:

To write the form of the partial fraction decomposition of the rational expression:

We have:

$\mathbf{\dfrac{8x-4}{x(x^2+1)^2}= \dfrac{A}{x}+\dfrac{Bx+C}{x^2+1}+\dfrac{Dx+E}{(x^2+1)^2}}$

Using partial fraction decomposition to find the definite integral of:

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}dx$

By using the long division method; we have:

$x^2-8x-20 | \dfrac{2x}{2x^3-16x^2-39x+20 }$

$- 2x^3 -16x^2-40x$

$x+ 20$

So;

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x+\dfrac{x+20}{x^2-8x-20}$

By using partial fraction decomposition:

$\dfrac{x+20}{(x-10)(x+2)}= \dfrac{A}{x-10}+\dfrac{B}{x+2}$

$= \dfrac{A(x+2)+B(x-10)}{(x-10)(x+2)}$

x + 20 = A(x + 2) + B(x - 10)

x + 20 = (A + B)x + (2A - 10B)

Now; we have to relate like terms on both sides; we have:

A + B = 1 ; 2A - 10 B = 20

By solvong the expressions above; we have:

$A = \dfrac{5}{2}$ $B = \dfrac{3}{2}$

Now;

$\dfrac{x+20}{(x-10)(x+2)} = \dfrac{5}{2(x-10)} + \dfrac{3}{2(x+2)}$

Thus;

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)}$

Now; the integral is:

$\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx = \int \begin {bmatrix} 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)} \end {bmatrix} \ dx$

$\mathbf{\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx = x^2 + \dfrac{5}{2}In | x-10|\dfrac{3}{2} In |x+2|+C}$

3. Due to the fact that the maximum words this text box can contain are 5000 words, we decided to write the solution for question 3 and upload it in an image format.

Please check to the attached image below for the solution to question number 3.

4 0

2 years ago