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fiasKO [112]
3 years ago
11

Shown here are four frequency distributions. Each is incorrectly constructed. State the reason why.

Mathematics
1 answer:
Tanya [424]3 years ago
8 0

Answer/Step-by-step explanation:

a. The the class width for the 1st, 2nd, 3rd, and 5th row equal 5 in the frequency distribution. Whereas, in the 4th row, the class width is 4 (49 - 45). This makes the construction incorrect.

b. Here, the upper limit of each consecutive class was used as the lower limit if the next class. For example, 9 is a member of the first class, which is the upper limit if the class in the first row, it ought not to be included as a member of the next class in the second row.

c. In the 3rd row, the lower limit of the class should be 133, NOT 138.

d. Different class width were used.

Row 1 class width = 13 - 9 = 4

Row 2 class width = 19 - 14 = 5

Row 3 class width = 25 - 20 = 5

Row 4 class width = 28 - 26 = 2

Row 5 class width = 32 - 29 = 3

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In a cohort of 35 graduating students, there are three different prizes to be awarded. If no student can receive more than one p
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We have been given in a cohort of 35 graduating students, there are three different prizes to be awarded. We are asked that in how many different ways could the prizes be awarded, if no student can receive more than one prize.

To solve this problem we will use permutations.

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We know that formula for permutations is given as

_{r}^{n}\textrm{P}=\frac{n!}{(n-r)!}

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3 years ago
8n + 12 - 5n = 21<br> n=?
insens350 [35]

Answer:

n=3

Step-by-step explanation:

Simplifying

8n + 12 + -5n = 21

Reorder the terms:

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Solving

12 + 3n = 21

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-12' to each side of the equation.

12 + -12 + 3n = 21 + -12

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3n = 21 + -12

Combine like terms: 21 + -12 = 9

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Divide each side by '3'.

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Simplifying

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