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musickatia [10]
3 years ago
11

Can someone help me with 5-6

Mathematics
1 answer:
olchik [2.2K]3 years ago
4 0

Answer:

B, C

Step-by-step explanation:

I love slope

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Tangent Line h(t) = sec t / t @ (Pi, 1/pi)
Alex Ar [27]
Take derivitive

note
the derivitive of sec(x)=sec(x)tan(x)
so
remember the quotient rule
the derivitive of \frac{f(x)}{g(x)} = \frac{f'(x)g(x)-g'(x)f(x)}{(g(x))^2}
so

the derivitive of \frac{sec(t)}{t} = \frac{sec(t)tan(t)t-(1)(sec(t))}{t^2}
so now evaluate when t=pi
we get
sec(pi)=-1
tan(pi)=0
we get
\frac{(-1)(0)(pi)-(pi)(-1)}{pi^2}= \frac{pi}{pi^2}= \frac{1}{pi}
slope=1/pi

use slope point form
for
slope=m and point is (x1,y1)
equation is
y-y1=m(x-x1)
slope is 1/pi
point is (pi,1/pi)

y-1/π=1/π(x-π)
times both sides by π
πy-1=x-π
πy=x-π+1
y=(1/π)x-1+(1/π)
or, alternately
-(1/π)x+y=(1/π)-1
x-πy=π-1
7 0
3 years ago
Ms. Moran has started an investment club at BSS. $8000 is invested, some at 10%
labwork [276]
The answer can be readily calculated using a single variable, x:

Let x = the amount being invested at an annual rate of 10%
Let (8000 - x) = the amount being invested at an annual rate of 12%

The problem is then stated as:

(x * 0.10) + ((8000 - x) * 0.12) = 900
0.10(x) + ((8000 * 0.12) - 0.12(x)) = 900
0.10(x) + 960 - 0.12(x) = 900
0.10(x) - 0.12(x) = 900 - 960
-0.02(x) = -60
-0.02(x) * -100/2 = -60 * -100/2
x = 6000 / 2
x = 3000

Thus, $3,000 is invested at 10% = $300 annually; and $8,000 - $3,000 = $5,000 invested at 12% = $600 annually, which sum to $900 annual investment.
6 0
2 years ago
#2 only <br> And it's to confusing
ipn [44]
They are easy to compare if they all have the same common denominator, then you can easily order them by the magnitude of the numerators...

85/10, -67/10, -56/10, 82/10  so now they are easy to compare...so

-6.7, -28/5, 8.2, 17/2
5 0
3 years ago
2 FOR 2.20 UNIT RATE
dlinn [17]

Answer: (if your asking for the unit rate of that)

the unit rate is 1.10

5 0
2 years ago
Need help before 5:30pm i also have to show my work.
SpyIntel [72]

I can help!! But could you tell me what the equations are?

6 0
3 years ago
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