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Fudgin [204]
3 years ago
5

Given an isosceles right triangle with side 6 m, what is the length of the hypotenuse?

Mathematics
1 answer:
Artemon [7]3 years ago
3 0

Answer: 6√2m or 8.49.

Step-by-step explanation:

Drawing the right angled triangle and label the sides, AC, which is the hypotenuse and the longest, AB , one if the sides, and BC the third sides. Since it is an isosceles right angle triangle with the right angle at B, based on my own diagram here, two of the sides are equal.

AB = BC = 6m

Now to find the hypotenuse, we apply the Pythagoras theorem which states that the square of the sum of the two sides equal the square of the hypotenuse side.That is

AC² = AB² + BC²

AC² = 6² + 6²

= 36. + 36

= 72

AC² = 72, Therefore, AC which is the hypotenuse

AC = √72

= √36 × √2

= 6√2m. or 8.49m

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3 years ago
3x + 4y = 27 5x - 3y = 16
Arturiano [62]

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Step-by-step explanation:

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{3 x + 4 y = 27 | (equation 1)

5 x - 3 y = 16 | (equation 2)

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{5 x - 3 y = 16 | (equation 1)

3 x + 4 y = 27 | (equation 2)

Subtract 3/5 × (equation 1) from equation 2:

{5 x - 3 y = 16 | (equation 1)

0 x+(29 y)/5 = 87/5 | (equation 2)

Multiply equation 2 by 5/29:

{5 x - 3 y = 16 | (equation 1)

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