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Sauron [17]
3 years ago
14

The directrix of a parabola is y=−4y=−4 . The focus of the parabola is (−2,−2)(−2,−2) .

Mathematics
1 answer:
salantis [7]3 years ago
6 0
Refer to the diagram shown below.

The directrix is y = -4 and the focus is (-2, -2).
Therefore the vertex is at (-2, -3).

Consider an arbitrary point (x,y) on the parabola.
The square of distance from the focus to the point is
(x+2)² + (y+2)²
The square of the distance from the point to the directrix is
(y+4)²

Therefore
(y+4)² = (y+2)² + (x+2)²
y² + 8y + 16 = y² + 4y + 4 + (x+2)²
4y = (x+2)² - 12
y = (1/4)(x+2)² - 3

Answer: y =  \frac{1}{4} (x+2)^{2} - 3

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Read 2 more answers
PLEASE HELP
Viefleur [7K]
7x²=9+x
so
for
0=ax²+bx+c

x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}
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mins 9 from both sides and minus x
7x²-1x-9=0
a=7
b=-1
c=-9


x=\frac{-(-1)+/-\sqrt{(-1)^2-4(7)(-9)}}{2(7)}
x=\frac{1+/-\sqrt{(-1)^2+4(7)(9)}}{2(7)}
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