If an angle measures x° what is its complement

Mathematics

1 answer:

Natali5045456 [20]3 years ago

7 0

90-x because a complementary angle is =90 degrees.

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A square garden is surrounded by a walkway of width X. If the area of the garden is 484 ft2 and the area covered by both the gar

slavikrds [6]

The width of the walkway is 3 feet, If the area of the garden is 484 $feet^{2}$ and the area covered by both the garden and the walkway (the entire square) is 784 $feet^{2}$ .

Step-by-step explanation:

The given is,

Area of the garden is 484 $feet^{2}$

Area covered by both the garden and the walkway (the entire square) is 784 $feet^{2}$ .

Let, x - Width of the walkway

Step:1

Formula to calculate area of square is,

$A= a^{2}$ ...........................(1)

Where, r - Radius of square

Step:2

For garden,

A = 484 $feet^{2}$

Equation (1) becomes,

$484=a^{2}$

Take square root on both sides,

$a=\sqrt{484}$

a = 22 feet

For garden and the walkway (the entire square),

A = 784 $feet^{2}$

Equation (1) becomes,

$784=a^{2}$

Take square root on both sides,

$a=\sqrt{784}$

a = 28 feet

Step:3

Ref attachment,

Side of garden and the walkway =

Side of garden + 2 (width of the walkaway)....(1)

28 = 22 + 2 ( x )

2 ( x ) = 28 - 22

= 6

$x = \frac{6}{2}$

Width, x = 3 feet

Result:

The width of the walkway is 3 feet, If the area of the garden is 484 $feet^{2}$ and the area covered by both the garden and the walkway (the entire square) is 784 $feet^{2}$ .