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3 years ago

If an angle measures x° what is its complement

Mathematics

1 answer:

Natali5045456 [20]3 years ago

7 0

90-x because a complementary angle is =90 degrees.

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In a right triangle, if the length of the hypotenuse is 39 and the length of one of the other sides is 15, what is the length of

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Answer:

<h3>either way the answer is be =36 so the length of the missing side is 36 CM. </h3>

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3 years ago

Which is a factor of each term of the polynomial? (72−12) CLEAR CHECK 7 2 7

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Answer:

Is the greatest factor

Step-by-step explanation:

All factors include

2,3,4,6,12

Thats it

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2 years ago

Three dentists wanted to compare the ages of their patients. They each calculated their patients’ mean age and the mean absolute

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Dr. Appiah’s patients’ ages vary less than do Dr. Singh’s patients’ ages.

GARBAGE DAY!

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2 years ago

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When the center of Earth is 3.8 × 105 kilometers from the center of the moon, the force of gravity between Earth and the moon is

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I think the answer to you question is 35 i might be wrong tho but it may work.

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2 years ago

Litter such as leaves falls to the forest floor, where the action of insects and bacteria initiates the decay process. Let A be

Travka [436]

Answer:

D = L/k

Step-by-step explanation:

Since A represents the amount of litter present in grams per square meter as a function of time in years, the net rate of litter present is

dA/dt = in flow - out flow

Since litter falls at a constant rate of L grams per square meter per year, in flow = L

Since litter decays at a constant proportional rate of k per year, the total amount of litter decay per square meter per year is A × k = Ak = out flow

So,

dA/dt = in flow - out flow

dA/dt = L - Ak

Separating the variables, we have

dA/(L - Ak) = dt

Integrating, we have

∫-kdA/-k(L - Ak) = ∫dt

1/k∫-kdA/(L - Ak) = ∫dt

1/k㏑(L - Ak) = t + C

㏑(L - Ak) = kt + kC

㏑(L - Ak) = kt + C' (C' = kC)

taking exponents of both sides, we have

$L - Ak = e^{kt + C'} \\L - Ak = e^{kt}e^{C'}\\L - Ak = C"e^{kt} (C" = e^{C'} )\\Ak = L - C"e^{kt}\\A = \frac{L}{k} - \frac{C"}{k} e^{kt}$

When t = 0, A(0) = 0 (since the forest floor is initially clear)

$A = \frac{L}{k} - \frac{C"}{k} e^{kt}\\0 = \frac{L}{k} - \frac{C"}{k} e^{k0}\\0 = \frac{L}{k} - \frac{C"}{k} e^{0}\\\frac{L}{k} = \frac{C"}{k} \\C" = L$

$A = \frac{L}{k} - \frac{L}{k} e^{kt}$

So, D = R - A =

$D = \frac{L}{k} - \frac{L}{k} - \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{kt}$

when t = 0(at initial time), the initial value of D =

$D = \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{k0}\\D = \frac{L}{k} e^{0}\\D = \frac{L}{k}$

4 0

2 years ago