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3 years ago

A rectangle has an area of 24x^3 and a length of 4x^2 meters. what is the width of the rectangle

Mathematics

1 answer:

lys-0071 [83]3 years ago

6 0

Answer:

Step-by-step explanation:

The area is given by the formula ...

A = LW

Fill in the given values and solve for width.

24x^3 = (4x^2)W

W = (24x^3)/(4x^2) = 6x

The width of the rectangle is 6x.

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Divide: (-7x+x^2+15)÷(-3+x)

kakasveta [241]

Since the divisor is in the form (x + #) or (x - #), This can be done by synthetic division.
First put the polynomial ion descending order: x^2 - 7x + 15
Take the coefficients of the terms and follow these steps:

3 | 1 -7 15
   3 -12
___________ Bring down the 1, multiply the 3 by the 1 and place under the
   1 -4    3 -7, then add.
   Multiply 3 by -4, place under the 15, then add.
   The bottom row is our answer. Since the problem started with a second power, the answer will start with a first power.
The bottom row are the coefficients of the terms and the last number is the remainder.
x - 4 remainder 3 ALSO WRITTEN x - 4 + 3/(x -3)

3 0

3 years ago

A set of kitchen containers can be stacked to save space. The height of the stack is given by the expression LaTeX: 1.5c+7.61.5

Nuetrik [128]

Answer:

Part A

The height of the stack made of 8 containers is 19.6 cm

Part B

When the tower is 40.6 cm tall, the number of containers in the set are 22 containers

Part C

(Disagree) The height of a single container is 9.1

Step-by-step explanation:

The question relates to containers, stacked one inside the other such that the height increases by only the wider top edge of the containers

The given expression that gives the height of the stack is presented as follows;

1.5·c + 7.6

Where;

c = The number of containers in the stack

Part A

When there are 8 containers, we have;

h(8) = 1.5 × 8 + 7.6 = 19.6

The height of the stack made of 8 containers, h(8) = 19.6 cm

Part B

When the tower (height of the stack set) is 40.6 cm tall, we have;

h(c) = 1.5·c + 7.6 = 40.6

∴ The number of containers, c = (40.6 - 7.6)/1.5 = 22

When the tower is 40.6 cm tall, the number of containers in the set, c = 22 containers

Part C

Given that the height stack increases only by the thickness of the wider rim of each added container, we have;

The expression for the height of the stack , 1.5·c + 7.6, is the expression for a straight line equation, m·x + c

The thickness of each rim = The slope, of the line, m = The increase in height with number of containers = 1.5

The number of containers (The independent variable, x) = The number of stacked rims = c

The minimum height = The height of a single container = 1.5 × 1 + 7.6 = 9.1

Therefore, the height of a single container = 9.1 not 7.6

4 0

2 years ago

Help (Picture attached)

Jlenok [28]

I think that its 36...

6 0

3 years ago

Read 2 more answers

For there are 48 apples and 60 bananas and 96 oranges each basket must contain the same number of each type of frut Search inste

vaieri [72.5K]

This question is incomplete

Complete Question

For there are 48 apples and 60 bananas and 96 oranges each basket must contain the same number of each type of fruit. Find the greatest number of baskets you can have

Answer:

The greatest number of baskets you can have is 12 baskets.

And each baskets would contain:

4 apples, 5 bananas and 8 oranges

Step-by-step explanation:

The factors of 48 are: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48

The factors of 60 are: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60

The factors of 96 are: 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 96

Then the greatest common factor is 12.

Therefore, the greatest number of baskets you can have is 12 baskets.

Each baskets would have

For apples

48 apples

48 apples / 12 baskets = 4 apples per basket

For bananas

60 bananas

60 bananas/12 baskets = 5 bananas per basket

For Oranges

96 Oranges/ 12 baskets = 8 oranges per baskets

8 0

3 years ago

Can someone tell me how to do this? with steps?

MrRa [10]

Answer:

Step-by-step explanation:

In Δ AFB,

∠AFB + ∠ABF + ∠A = 180 {Angle sum property of triangle}

90 + 48 + ∠1 = 180

138 + ∠1 = 180

∠1 = 180 - 138

∠1 = 42°

FC // ED and FD is transversal

So, ∠CFD ≅∠EDF {Alternate interior angles are congruent}

∠2 = 39°

In ΔFCD,

∠2 + ∠3 + ∠FCD = 180

39 + ∠3 + 90 = 180

129 +∠3 = 180

∠3 = 180- 129

∠3 = 51°

3 0

2 years ago