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3 years ago

Need help on this question (:

Mathematics

1 answer:

Colt1911 [192]3 years ago

8 0

See this and Mark as brainleist please

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Help me with this please

lutik1710 [3]

<h3>Answer:</h3>

4.42×10^34 molecules/min

<h3>Step-by-step explanation:</h3>

Multiply the various factors, along with the unit conversion (60 s/min).

... (3.35×10^25 molecules/L) × (2.2×10^7 L/s) × (60 s/min)

... = (3.35×2.2×60)×10^(25+7) molecules/min

... = 442.2×10^32 molecules/min

... ≈ 4.42×10^34 molecules/min

_____

<em>Comment on scientific notation problems</em>

Your scientific or graphing calculator will allow you to enter and display numbers in scientific notation.

7 0

3 years ago

The endpoints of a side of rectangle ABCD in the coordinate plane are at A(1,4) and

andrew-mc [135]

Answer:

Step-by-step explanation:

A(1, 4)

B(4, 1)

$m_{AB}$ = $\frac{1-4}{4-1}$ = - 1

y - 1 = - 1 ( x - 4 )

<em>y = - x + 5</em>

6 0

2 years ago

Identify the vertex, axis of symmetry, minimum or maximum, domain, and range of the function f(

alekssr [168]

Identify the vertex, axis of symmetry, minimum or maximum, domain, and range of the function ()=−(+)^−

<em><u>Answer:</u></em>

vertex = (-4, -5)

Axis of symmetry = -4

use the (-4, -5) to find the minimum value

$Domain = ( - \infty, \infty ) , [ x | x\ is\ real ]\\\\Range = [ -5, \infty ), y\geq -5$

<em><u>Solution:</u></em>

Given function is:

$f(x) = (x+4)^2 - 5$

The equation in vertex form is given as:

$y = a(x-h)^2+k$

Where, (h, k) is constant

On comparing give function with vertex form,

h = -4

k = -5

Vertex is (-4 , -5)

Axis of symmetry : x co-ordinate of vertex

Thus, axis of symmetry = -4

The coefficient of x^2 is positive in given function.

Thus the vertex point will be a minimum

$Minimum\ value = f(\frac{-b}{a})$

$f(x) = x^2 + 8x + 16 - 5\\\\f(x) = x^2 + 8x + 11$

$f(x) = ax^2+bx+c$

On comparing,

a = 1

b = 8

$x = \frac{-b}{2a} = \frac{-8}{2 \times 1} = -4$

$f(-4) = (-4)^2 + 8(-4) + 11 = 16 - 32 + 11 = -5$

Thus, use the (-4, -5) to find the minimum value

Domain and range

$f(x) = (x+4)^2 - 5$

The domain is the input values shown on the x-axis

The range is the set of possible output values f(x)

Therefore,

$Domain = ( - \infty, \infty ) , [ x | x\ is\ real ]\\\\Range = [ -5, \infty ), y\geq -5$

4 0

2 years ago

Assuming thay line WXZ is straight, what are the measure and classification of angle YXZ?

Talja [164]

It’s b.
because it’s would be 180-45

8 0

3 years ago

Find the volume of the cubes or rectangular prisms in cubic centimeters.

DanielleElmas [232]

a) Volume of Rectangular prism is $\frac{36}{125}\,\,cm^3$

b) Volume of cube is $\frac{8}{125}\,\,cm^3$

c) Volume of cube is $\frac{1}{125}\,\,cm^3$

d) Volume of Rectangular prism is $\frac{6}{125}\,\,cm^3$

Step-by-step explanation:

Part a)

Volume of rectangular prism with

length= $\frac{3}{5}\,\,cm$

width= $\frac{4}{5}\,\,cm$

height = $\frac{3}{5}\,\,cm$

The formula used to find Volume of rectangular prism is:

$Volume\,\,of\,\,rectangular\,\,prism=length*width*height$

Putting values:

$Volume\,\,of\,\,rectangular\,\,prism=\frac{3}{5} *\frac{4}{5} *\frac{3}{5}\\Volume\,\,of\,\,rectangular\,\,prism=\frac{36}{125}\,\,cm^3$

So, Volume of Rectangular prism is $\frac{36}{125}\,\,cm^3$

Part b)

Volume of cube with side length of $\frac{2}{5}\,\,cm$

The formula used to find Volume of cube is:

$Volume\,\,of\,\,cube=length^3$

Putting value of length and finding volume:

$Volume\,\,of\,\,cube=length^3\\Volume\,\,of\,\,cube=(\frac{2}{5})^3\\ Volume\,\,of\,\,cube=\frac{8}{125}\,\,cm^3$

So, Volume of cube is $\frac{8}{125}\,\,cm^3$

Part c)

Volume of cube with side length of $\frac{1}{5}\,\,cm$

The formula used to find Volume of cube is:

$Volume\,\,of\,\,cube=length^3$

Putting value of length and finding volume:

$Volume\,\,of\,\,cube=length^3\\Volume\,\,of\,\,cube=(\frac{1}{5})^3\\ Volume\,\,of\,\,cube=\frac{1}{125}\,\,cm^3$

So, Volume of cube is $\frac{1}{125}\,\,cm^3$

Part d)

Volume of rectangular prism with

length= $\frac{1}{5}\,\,cm$

width= $\frac{2}{5}\,\,cm$

height = $\frac{3}{5}\,\,cm$

The formula used to find Volume of rectangular prism is:

$Volume\,\,of\,\,rectangular\,\,prism=length*width*height$

Putting values:

$Volume\,\,of\,\,rectangular\,\,prism=\frac{1}{5} *\frac{2}{5} *\frac{3}{5}\\Volume\,\,of\,\,rectangular\,\,prism=\frac{6}{125}\,\,cm^3$

So, Volume of Rectangular prism is $\frac{6}{125}\,\,cm^3$

Keywords: Volume

Learn more about Volume at:

#learnwithBrainly

6 0

3 years ago