The answer to your question would be, 22 31/32 because you would multiply 2 5/8 and 8 3/4.
To=mutiply.
Hope I helped:-)
The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118 .
In the question ,
it is given that ,
the probability of committing at least , type I error is = 0.7
we have to find the number of tests ,
let the number of test be n ,
the above mentioned situation can be written as
1 - P(no type I error is committed) ≥ P(at least type I error is committed)
which is written as ,
1 - (1 - 0.01)ⁿ ≥ 0.7
-(0.99)ⁿ ≥ 0.7 - 1
(0.99)ⁿ ≤ 0.3
On further simplification ,
we get ,
n ≈ 118 .
Therefore , the number of tests are 118 .
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Answer:
(3 oz ; 4oz)
Step-by-step explanation:
Given that :
Mean = 3.5 oz
Standard deviation = 0.5 oz
According to the empirical rule ; 68% is 1 standard deviation from the mean.
Hence, the interval that would represent the middle 68% will be:
(3.5 oz - 0.5 oz) ; (3.5 oz + 0.5oz)
(3 oz ; 4oz)
