The answer is the third one which would be x is less then or equal to 5
If tan(<span>θ) is negative, then </span><span>θ must be either in Q-II or else in Q-IV.
Fortunately, the question tells us that it's in Q-II.
If you draw a circle on the x- and y-axes, then draw a right triangle
in Q-II, then mark the legs 3 and -2, then the hypotenuse of the
triangle ... also the radius of the circle ... is √13 .
Look for the angle whose tangent is -3/2.
tangent = (opposite) / (adjacent)
So the side opp</span>osite is the 3 and the side adjacent is the -2.
For that same angle, cosine = (adjacent) / (hypotenuse) .
The adjacent side is still the -2, and the hypotenuse is √13 .
So the cosine of the same angle is
- 2 / √13 .
To rationalize the denominator (get that square root out of there),
multiply top and bottom by √13 . Then you have
(- 2 / √13) · (√13 / √13)
= - 2 √13 / 13 .
We know that if (x,y) lies on the graph of a function, then (y,x) lies on the graph of its inverse.
This means you need to draw the segment with endpoints (9,1) and (2,3).
If I knew the answer I would helped u b,
ut I'm only in 7th grade but I will try
30,398.40. I think 6.85%-6.475%=0.375%x3/30. Then $340,000- the numbers.
