Solve the following equation for x. x2 + 8x + 7 = 0

Which pyramids with base area B and height h have equal volumes.

Reptile [31]

C and D

the volume ( V) of a pyramid is found using the formula

V = $\frac{1}{3}$ × area of base × height

calculating each of the volumes gives

(A) V = $\frac{1}{3}$ × 10.5 × 6 = 21 in³

(B) V = $\frac{1}{3}$ × 3.6 × 8 = 9.6 in³

(C) V = $\frac{1}{3}$ × 4.2 × 12 = 16,8 in³

(D) V = $\frac{1}{3}$ × 6 × 8.4 = 16.8 in³

C and D have equal volumes

5 0

3 years ago

A gallon or unleaded gasoline weights about 6 pounds about how many ounces does 1 quart of unleaded gasoline weight hint= 1/4 ga

alexira [117]

i think the answer is 1/4 because it good

3 0

3 years ago

Read 2 more answers

1. Write a differential equation describing the following situation:

jenyasd209 [6]

Answer:

dP/dt = k*(600 - P)*P

Step-by-step explanation:

Given:

- Total number of people in company N = 6000

- Total people involved in bribery P

The rate at which people become involved in a corporate bribing scheme is jointly proportional to the number of people already involved and the number of people who are not yet involved.

Find:

Write a differential equation

Solution:

- The following differential equation can be used to describe the situation above:

Number of people not affected = N - P

- Hence we can write a differential equation:

dP/ dt = k *( N - P )*P

- input the value of N:

dP/dt = k*(600 - P)*P

8 0

4 years ago

Which ratio represents Sin A?

Marysya12 [62]

Answer:

sin A = 56/ 65

Step-by-step explanation:

sin of an angle = opposite side to the angle / hypothenuse

sin A = 56/ 65

4 0

3 years ago

An ordinary (fair) die is a cube with the numbers 1 through 6 on the sides (represented by painted spots). Imagine that such a d

irina1246 [14]

<h2>Event A:</h2><h3>Pairs that make the sum greater than 8:</h3>

(3,6) (4,6) (5,6) (6,6) (4,5) (5,5)

<u>Each of these pairs is </u><u>equiprobable</u><u> and which i will be using throughout the exercise</u>:

$p(pair) = \frac{1}{6} \times \frac{1}{6} = \frac{1}{36}$

$p(a) = (\frac{1}{36} \times 2) \times 4 + \frac{1}{36} \times 2 = \frac{5}{18}$

The 2 (2!) is to account for permutations like ( 3 , 6 ) and ( 6 , 3 ) and the 4 are the different combinations that are composed of different numbers.

The 2 (2!) is to account for permutations like ( 3 , 6 ) and ( 6 , 3 ) and the 4 are the different combinations that are composed of different numbers.Whereas combinations like ( 5 , 5 ) cannot be switched in order, so we do not multiply by 2!

<h2>Event B</h2><h3>Pairs that yield a sum divisible by 4 or 5: 0,4,5,8,10,12,</h3>

(1,3) (2,2) (2,6) (4,4) (5,3) (6,6) (1,4) (2,3) (5,5) (4,6)

$p(not \: b) = ( \frac{1}{36} \times 2) \times 6 + \frac{1}{36} \times 4 = \frac{4}{9}$

$p(b) = 1 - p(not \: b) = 1 - \frac{4}{9} = \frac{5}{9}$

8 0

2 years ago