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horrorfan [7]
3 years ago
12

To help divide a group into 4 teams, the teacher brought out a bag with equal numbers of 4 different colored popsicle sticks (gr

een, yellow, blue, and red). With 28 students randomly picking a stick, what is the probability that the first stick drawn will be green? A. 0.250 B. 0.571 C. 0.036 D. 0.143
Mathematics
1 answer:
NeX [460]3 years ago
3 0
The set of all possible events Ω

Ω = 24 ( 4*7 = 28 stick)

<span>set of events favorable A
A = 7 ( </span><span>sticks of green is 7)

</span><span>Probability P
P(A) = A/</span>Ω = 7/28 = 1/4 = 0,25

Answer A
<span>The first person has the ability to draw seven green sticks of twenty-four </span>
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Answer: 0=2x^2-7x-9\\0=4x^2-3x-1\\0=x^2-2x-8


Step-by-step explanation:

We know that the standard quadratic equation is  ax^2+bx+c=0

Let's compare all the given equation to it and , find discriminant.

1. a=2, b= -7, c=-9

b^2-4ac=(-7)^2-4(2)(-9)=49+72>0

So it has 2 real number solutions.

2. a=1, b=-4, c=4

b^2-4ac=(-4)^2-4(1)(4)=16-16=0

So it has only 1 real number solution.

3. a=4, b=-3, c=-1

b^2-4ac=(-3)^2-4(4)(-1)=9+16=25>0

So it has 2 real number solutions.

4. a=1, b=-2, c=-8

b^2-4ac=(-2)^2-4(1)(-8)=4+32=36>0

So it has 2 real number solutions.

5. a=3, b=5, c=3

b^2-4ac=(5)^2-4(3)(3)=25-36=-9

Thus it does not has real solutions.



5 0
3 years ago
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The dimensions for a rectangular prism are x + 2 for the length, x + 3 for the width, and x for the height. What is the volume o
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V = lwh

V = (x + 2)(x + 3)(x)

V = (x)(x^2 + 3x + 2x + 6)

V = (x^3 + 3x^2 + 2x^2 + 6x)

V = x^3 + 5x^2 + 6x

All you do is foil the dimensions together and then combine like terms. Hope this helps!
7 0
2 years ago
Which statement is true?
gayaneshka [121]

Answer:

Option: C is the correct answer.

C. Buying a needle and buying thread are dependent events.

Step-by-step explanation:

let A denotes the events of buying a thread.

and B denote the event of buying a needle.

Then A∩B denote the event of buying a needle and  a thread.

Also let P denote the probability of an event.

i.e. we are given:

P(A)=0.15

Also P(B|A)=0.25

As we know that:

P(B|A)=\dfrac{P(A\bigcap B)}{P(A)}\\\\i.e.\\\\0.25=\dfrac{P(A\bigcap B)}{0.15}\\\\i.e.\\\\P(A\bigcap B)=0.0375

As we know that when two events A and B are independent then,

P(A∩B)=∅

otherwise they are dependent events.

Hence, option: C is the correct answer.

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3 years ago
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The prices of all college textbooks follow a bell-shaped distribution with a mean of $113 and a standard deviation of $12. Using
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Step-by-step explanation:

In statistics, the empirical rule states that for a normally distributed random variable,

  • 68.27% of the data lies within one standard deviation of the mean.

  • 95.45% of the data lies within two standard deviations of the mean.

  • 99.73% of the data lies within three standard deviations of the mean.

In mathematical notation, as shown in the figure below (for a standard normal distribution), the empirical rule is described as

                             \Phi(\mu \ - \ \sigma \ \leq X \ \leq \mu \ + \ \sigma) \ = \ 0.6827 \qquad (4 \ \text{s.f.}) \\ \\ \\ \Phi(\mu \ - \ 2\sigma \ \leq X \ \leq \mu \ + \ 2\sigma) \ = \ 0.9545 \qquad (4 \ \text{s.f.}) \\ \\ \\ \Phi}(\mu \ - \ 3\sigma \ \leq X \ \leq \mu \ + \ 3\sigma) \ = \ 0.9973 \qquad (4 \ \text{s.f.})

where the symbol \Phi (the uppercase greek alphabet phi) is the cumulative density function of the normal distribution, \mu is the mean and \sigma is the standard deviation of the normal distribution defined as N(\mu, \ \sigma).

According to the empirical rule stated above, the interval that contains the prices of 99.7% of college textbooks for a normal distribution N(113, \ 12),

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Therefore, the price of 99.7% of college textbooks falls inclusively between $77 and $149.

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