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babymother [125]

3 years ago

13

What is the base area of a cube prisim 5mm

1 answer:

olga2289 [7]3 years ago

3 0

The answer is a = 0.91

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CAN SOMEONE HELP ME IN ALGEBRA PLEASE!

Reptile [31]

19,7,and 61 im not sure about the last one

8 0

2 years ago

The domain of both f(x) = x - 6 and g(x) = x + 6 is all real numbers. What is the domain of h(x) = ?

dolphi86 [110]

The denominator of a fraction cannot be zero.Therefore in h(x) = f(x)/g(x), g(x) cannot equal zero, x + 6 cannot equal zero, x cannot equal -6. The domain of h(x) is ℜ - {-6}.

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

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3 years ago

on Wednesday jean's nursery received a shipment of 60 flowering crabapple trees. jean has ordered 80 trees. what percent of her

WITCHER [35]

75% when you have 60/80

7 0

3 years ago

find the values of the six trigonometric functions for angle theta in standard position if a point with the coordinates (1, -8)

frutty [35]

Answer:

cosФ = $\frac{1}{\sqrt{65}}$ , sinФ = $-\frac{8}{\sqrt{65}}$ , tanФ = -8, secФ = $\sqrt{65}$ , cscФ = $-\frac{\sqrt{65}}{8}$ , cotФ = $-\frac{1}{8}$

Step-by-step explanation:

If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:

cosФ = $\frac{x}{r}$
sinФ = $\frac{y}{r}$
tanФ = $\frac{y}{x}$
secФ = $\frac{r}{x}$
cscФ = $\frac{r}{y}$
cotФ = $\frac{x}{y}$

Where r = $\sqrt{x^{2}+y^{2} }$ (the length of the terminal side from the origin to point (x, y)

You should find the quadrant of (x, y) to adjust the sign of each function

∵ Point (1, -8) lies on the terminal side of angle Ф in standard position

∵ x is positive and y is negative

→ That means the point lies on the 4th quadrant

∴ Angle Ф is on the 4th quadrant

∵ In the 4th quadrant cosФ and secФ only have positive values

∴ sinФ, secФ, tanФ, and cotФ have negative values

→ let us find r

∵ r = $\sqrt{x^{2}+y^{2} }$

∵ x = 1 and y = -8

∴ r = $\sqrt{x} \sqrt{(1)^{2}+(-8)^{2}}=\sqrt{1+64}=\sqrt{65}$

→ Use the rules above to find the six trigonometric functions of Ф

∵ cosФ = $\frac{x}{r}$

∴ cosФ = $\frac{1}{\sqrt{65}}$

∵ sinФ = $\frac{y}{r}$

∴ sinФ = $-\frac{8}{\sqrt{65}}$

∵ tanФ = $\frac{y}{x}$

∴ tanФ = $-\frac{8}{1}$ = -8

∵ secФ = $\frac{r}{x}$

∴ secФ = $\frac{\sqrt{65}}{1}$ = $\sqrt{65}$

∵ cscФ = $\frac{r}{y}$

∴ cscФ = $-\frac{\sqrt{65}}{8}$

∵ cotФ = $\frac{x}{y}$

∴ cotФ = $-\frac{1}{8}$

8 0

2 years ago

The following table shows the number of snow days each school district in Mill County had last winter.

shtirl [24]

Answer:

The answer is 5.

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers