Answer:
The cost to supply enough vanillin so that the aroma could be detected in a large aircraft hangar with a volume of 5.95 x 10^7 ft^3 is $ 0.07.
Step-by-step explanation:
The volume of the hangar is
The minimal amount of vainilla needed to be detected in the hangar is equivalent to the threshold multiplied by the volume of the hangar:
The cost of this amount of vainilla is
The cost to supply enough vanillin so that the aroma could be detected in a large aircraft hangar with a volume of 5.95 x 10^7 ft^3 is $ 0.07.
Answer:
Step-by-step explanation:
∠DEF is congruent to ∠EFA
-2(2(5x - 9) -3 (2x + 5))
-2 (10x - 18 - 3 (2x + 5))
-2 (4x -18 -15
Answer = -2(4x - 33)
Answer:
a) The 90% confidence interval for the mean noise level at such locations
(112.46 , 163.54)
b) The critical value that should be used in constructing the confidence interval
Z₀.₁₀ = 1.645
Step-by-step explanation:
<u><em>Step(i)</em></u> :-
Noise levels at 3 airports were measured in decibels yielding the following data
108 146 160
Mean of given data
x : 108 146 160
x-x⁻ : -30 8 22
(x-x⁻ )² : 900 64 484
Variance σ ² = ∑(x-x⁻ )²/ n-1
= 
Standard deviation
σ = √724 = 26.90
<u><em>Step(ii):</em></u>-
The 90% confidence interval for the mean noise level at such locations
The critical value that should be used in constructing the confidence interval
Z₀.₁₀ = 1.645
( 138 - 25.54 , 138 + 25.54 )
(112.46 , 163.54)
