Ok, here we go. Pay attention. The formula for the arc length is

. That means that to use that formula we have to find the derivative of the function and square it. Our function is y = 4x-5, so y'=4. Our formula now, filled in accordingly, is

(that 1 is supposed to be negative; not sure if it is til I post the final answer). After the simplification we have the integral from -1 to 2 of

. Integrating that we have

from -1 to 2.

gives us

. Now we need to do the distance formula with this. But we need 2 coordinates for that. Our bounds are x=-1 and x=2. We will fill those x values in to the function and solve for y. When x = -1, y=4(-1)-5 and y = -9. So the point is (-1, -9). Doing the same with x = 2, y=4(2)-5 and y = 3. So the point is (2, 3). Use those in the distance formula accordingly:

which simplifies to

. The square root of 153 can be simplified into the square root of 9*17. Pulling out the perfect square of 9 as a 3 leaves us with

. And there you go!
(1)
10(1+3x)=-20
Cross multiply.
10+30x=-20
Isolate x on one side. So you would subtract 10 on each side. and one side will cross each other out. leaving you with,
30x=-20-10
Subtract 10 from -20.
30x=-30
Divide each side by 30 to get x.
30x÷30=-30÷30
Therefore,
x=-1
(2)
-5x-8(1+7x)=-8
Cross multiply -8(1+7x)
-5x-8-56x=-8
Isolate all x's on one side. So you would add 8 on each side. and one side will cross each other out. leaving you with,
-5x-56x=-8+8
Add 8 to -8.
-5x-56x=0
Subtract -56x from -5x
-61x=0
Divide each side by -61
-61x÷-61=0÷-61
Therefore,
x=0
<h3>Answer :- </h3>
<h3>Solution :- </h3>
- 2x + 42 = 90
- 2x = 90 - 42
- 2x = 48
- x = 48/2
- x = 24
<em>Hope</em><em> it</em><em> helps</em><em> </em><em>~</em>
I’m pretty sure it’s 60 degrees because in the question it is implying that both triangles are equal so whatever goes for one triangle goes for the other